Answer:
Degree of numerator is less than degree of denominator: horizontal asymptote at y = 0. Degree of numerator is greater than degree of denominator by one: no horizontal asymptote; slant asymptote. Degree of numerator is equal to degree of denominator: horizontal asymptote at ratio of leading coefficients.
Step-by-step explanation: Correct me if i'm wrong lol.
Answer:
R(t)=10+0.50t
Step-by-step explanation:
His rate is based on time, for the first side of the equation.
His beginning pay would be 10, so 10 would act as the y intercept. The rate increases by 0.50, so for every year (t) it would increase by 0.50, why you add 0.50 and multiply by the amount of years he works.
Supplementary angles = Angles that add up to 180°.
∠5 + ∠7 = 180° ← supplementary angles
∠1 = ∠5
Since ∠5 + ∠6 = 180°
⇒ ∠1 and ∠6 will also be 180° . ← supplementary angles
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Answer: ∠5 + ∠7 (Answer D) and ∠1 + ∠6 (Answer A)
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Answer:
us set up the following variables:
⎧
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎩
l
Length of Rectangle (cm)
w
Width of Rectangle (cm)
A
Area of Rectangle (
c
m
2
)
t
Time (s)
We are told that:
d
l
d
t
=
8
cm/s (const), and,
d
w
d
t
=
3
cm/s (const)
The Area of the rectangle is:
A
=
l
w
Differentiating wrt
t
(using the product rule) we get;
d
A
d
t
=
(
l
)
(
d
w
d
t
)
+
(
d
l
d
t
)
(
w
)
∴
d
A
d
t
=
3
l
+
8
w
So when
l
=
20
and
w
=
10
⇒
d
A
d
t
=
3
⋅
20
+
8
⋅
10
∴
d
A
d
t
=
60
+
80
∴
d
A
d
t
=
140
cm
There are many equations that equal 7 but here are a few
3+4=7
15-8=7
3.5*2=7
49/7=7
-35/-5=7
