We have two fractions being divided. When we divide two fractions, we flip the second fraction and multiply
1/12 divided by 1/6 = 1/12 * 6/1
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From here we multiply straight across.
The numerators multiply to get 1*6 = 6
The denominators multiply to 12*1 = 12
We end up with 6/12 which reduces to 1/2 when you divide both parts by the GCF 6
<h3>Final Answer: 1/2</h3>
Answer:
IK
Step-by-step explanation:
If you draw out the triangles it is easier to see
The <em><u>correct answer</u></em> is:
AAS
Explanation:
AAS stands for "angle-angle-side." This states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of another triangle, then the triangles are congruent.
In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with. Throughout the proof, we find that ∠ABC ≅ ∠DCB. We also have that CB is congruent to itself. This is two angles and a side not included, so this is AAS.
X = y + 11
2x + y = -2
2(y + 11) + y = -2
2y + 22 + y = -2
3y + 22 = -2
3y = -24
y = -8
x = y + 11
x = -8 + 11
x = 3
Solution set {3, -8} (C)
If (y-1) is a factor of f(y), f(y)=0 when y=1. So if you find that f(1)=0, then (y-1) is a factor of f(y).
f(y)=y^3-9y^2+10y+5
f(1)=1-9+10+5=7
Since f(1)=7, (y-1) is not a factor.
