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zvonat [6]
3 years ago
14

Find the height of a cuboid whose volume is 540cu.cm and base area is 90sq.cm

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

6 cm

Step-by-step explanation:

Vcuboid  = lwh

⇒ h = Vcuboid ÷ lw

∴  h = 540 cm³ ÷ 90 cm²

⇒ h = 6 cm

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If DF = 9x -39 find EF
Klio2033 [76]

|DF| = |DE| + |EF|

|DF| = 9x -36

|DE| = 47

|EF| = 3x+10

Substitute:

9x - 39 = 47 + 3x + 10

9x - 39 = 3x + 57     |+39

9x = 3x + 96    |-3x

6x = 96    |:6

x = 16

Put the value of x to the equation |EF| = 3x + 10

|EF| = (3)(16) + 10 = 48 + 10 = 58

Answer: |EF| = 58

7 0
3 years ago
Read 2 more answers
Someone please help me!​
ziro4ka [17]

Answer:

12. DE

13. DE

14. BE

15. DE

16. BC

Step-by-step explanation:

A midsegment is a line drawn across a triangle from one side to another that is parallel to the third side. It is also half the length of the parallel side. Here it is called DE.

7 0
3 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
3 years ago
Can anyone help me with these?
Lapatulllka [165]

Answer:

im sorry i have no idea

Step-by-step explanation:

6 0
3 years ago
Alex has a box of pens and pencils. Of all his pens and pencils,
drek231 [11]

Answer:

a. p = n + m

where: n is the number of pens, and m is the number of pencils

b. p = 71

Step-by-step explanation:

Let the number of pens  and pencils that Alex has be represented by n and m respectively.

But,

number of pens, n = 14

number of pencils, m = 57

Then,

total number of pens and pencils, p = number of pens + number of pencils

i.e p = n + m

p = 14 + 57

p = 71

The total number of pens and pencils that Alex has is 71.

7 0
2 years ago
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