Is there a picture with it?
Answer:
10
Step-by-step explanation:
Answer:
1.2
Step-by-step explanation:
1 
=1.2
Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
_____
If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Answer:
y= 3 when x= 0
y=3
Step-by-step explanation:
in the problem, there's a patten in the difference of X and Y,
at first, Y is 3 more than X (2 and 5)
then y is 4 more, 5 more, and 6 more.
y goes up by 1 each time
so if Y is 5 when X is 2, then when X is 1 Y is 4
when X is 0 Y is 3
