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Mathematics

2 answers:

scoundrel [369]3 years ago

7 0

Answer:

Step-by-step explanation:

Cloud [144]3 years ago

4 0

Answer - C

The slope is 4 since you can count up 4 and over 1 from the y intercept

The y intercept is 0,2 since it starts at 2

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PLEASE HELP! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER

Naddik [55]

Answer:

180

Step-by-step explanation:

for 40 to be equal to 80 in percentages, the number has to be duplicated

3 0

3 years ago

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Evaluate 48 + 24 ÷ 8 − 22

Licemer1 [7]

Answer:

Using PEMDAS, we would first divide 24/8=3. Then, since there is no multiplication or division left, we can finish up with adding and subtracting. So, 48+3-22=29.

So 29 is the answer.

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3 years ago

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12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$