Given:
0.607 mol of the weak acid
0.609 naa
2.00 liters of solution
The solution for finding the ph of a buffer:
[HA] = 0.607 / 2.00 = 0.3035 M
[A-]= 0.609/ 2.00 = 0.3045 M
pKa = 6.25
pH = 6.25 + log 0.3045/ 0.3035 = 6.25 is the ph buffer prepared.
Explanation:
The number of moles of solute present in liter of solution is defined as molarity.
Mathematically, Molarity = 
Also, when number of moles are equal in a solution then the formula will be as follows.

It is given that
is 8.00 M,
is 7.00 mL, and
is 0.80 M.
Hence, calculate the value of
using above formula as follows.



= 70 ml
Thus, we can conclude that the volume after dilution is 70 ml.
233.1g
Explanation:
Given:
Formula units of FeCl₃ = 8.65 x 10²³ formula units
Unknown:
Mass of the FeCl₃ = ?
Solution:
The formula unit is the same as the amount of subatomic particles in an atom.
1 mole of a substance = 6.02 x 10²³ formula units
For 8.65 x 10²³ formula units; the number of moles;
Number of moles =
= 1.44moles
Now to find the mass of FeCl₃;
Mass of FeCl₃ = 1.44 x 162.2 = 233.1g
learn more:
Number of moles brainly.com/question/1841136
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<span>The following acids do NOT ionize completely in solution because they are not strong acids are as follows:
a HBr
b HI
c H2SO3
d H3N
e HNO2
f HF
</span>