Keri has to identify a mysterious brown liquid in science class. She pours it through a filter, but the substance looks the same
2 answers:
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Explanation:
As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.
Hence, calculate the molecular weight of the mixture as follows.
Weight =
= 27.8336 g/mol
And, molar flow rate of air and mixture is calculated as follows.
= 28.74 kmol/hr
Now, applying component balance as follows.
= 43.11 kmol/hr
= 43.11 - 28.74
= 14.37 kmol/hr
So, mass flow rate of pure (B), is =
= 416.73 kg/hr
According to the product stream, 6 mol% A and 94 mol% B is there.
Molecular weight of product stream =
=
= 28.22 g/mol
Mass of product stream = 1216.67 kg/hr
Hence, mole of into the product stream is as follows.
=
= 272.31 kg/hr
Therefore, calculate the mass % of into the stream as follows.
= 22.38%
Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of in the product gas is 22.38%.
Answer:
M = 3.69 M.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:
Which gives molar units, M, or just mol/L.
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