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Montano1993 [528]
3 years ago
14

All energy originates from the _______.

Chemistry
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

sun

Explanation:

because all plants use energy from the sun to make food and grow

stich3 [128]3 years ago
5 0
C(sun) all energy originated from the sun
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You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca
vova2212 [387]
The equation to be used are:

PM = ρRT
PV = nRT
where
P is pressure, M is molar mass, ρ is density, R is universal gas constant (8.314 J/mol·K), T is absolute temperature, V is volume and n is number of moles

The density of air at 23.5°C, from literature, is 1.19035 kg/m³. Its molar mass is 0.029 kg/mol.

PM = ρRT
P(0.029 kg/mol) = (1.19035 kg/m³)(8.314 J/mol·K)(23.5+273 K)
P = 101,183.9 Pa

n = 0.587 g * 1 kg/1000 g * 1 mol/0.029 kg = 0.02024 mol
(101,183.9 Pa)V = (0.02024 mol)(8.314 J/mol·K)(23.5+273 K)
Solving for V,
V = 4.931×10⁻⁴ m³
Since 1 m³ = 1000 L
V = 4.931×10⁻⁴ m³ * 1000
V = 0.493 L

7 0
3 years ago
Please help me ill give brainiest to the right answer
valina [46]

Answer:

its c or a

Explanation:

7 0
3 years ago
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The partial pressure of cartbon dioxide in the atmgsphere is 0239 toer Caiculate the partial pressure in mm He and atm Rpund eac
Verizon [17]

Answer :

The pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

The pressure of carbon dioxide in the atmosphere in atm is 3.14\times 10^{-4}atm.

Explanation :

The conversion used for pressure from torr to mmHg is:

1 torr = 1 mmHg

The conversion used pressure from torr to atm is:

1 atm = 760 torr

or,

1torr=\frac{1}{760}atm

As we are given the pressure of carbon dioxide in the atmosphere 0.239 torr. Now we have to determine the pressure of carbon dioxide in the atmosphere in mmHg and atm.

<u>Pressure in mmHg :</u>

As, 1torr=1mmHg

So, 0.239torr=\frac{0.239torr}{1torr}\times 1mmHg=0.239mmHg

Thus, the pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

<u>Pressure in atm:</u>

As, 1torr=\frac{1}{760}atm

So, 0.239torr=\frac{0.239torr}{1torr}\times \frac{1}{760}atm=3.14\times 10^{-4}atm

Thus, the pressure of carbon dioxide in the atmosphere in atm is 3.14\times 10^{-4}atm.

3 0
2 years ago
TRUE or FALSE: Units in the Sl system include feet, pounds, and<br> degrees.<br><br> True<br> False
luda_lava [24]

Answer:

true true true true true

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2 years ago
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Sarah added sugar to her iced tea but it is not dissolveing very quickly which can Sarah do to make the sugar dissolve faster ?
Aliun [14]
Stir it,
Or as warmer water makes solutes dissolve faster Sarah can do that
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