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3 years ago

Hey. ill give brainliest to whoever answers this question, pls and thanks

Mathematics

2 answers:

abruzzese [7]3 years ago

8 0

Answer:

I don't see an answer.

Step-by-step explanation:

lbvjy [14]3 years ago

3 0

Answer:

whats the question

Step-by-step explanation:

You might be interested in

What is 11mp in expanded form

Flauer [41]

Answer:

<h3>Eleven-per miles who doesn't know that or 11.✌️</h3>

4 0

3 years ago

An algorithm takes 0.5 seconds to run on an input of size 100. How long will it take to run on an input of size 1000 if the algo

dexar [7]

Answer:

linear: 5s

quadratic: 50s

log-linear: 0.75 s

cubic: 500s

Step-by-step explanation:

Let $t_1,t_2$ be the running time associated with the input of sizes $s_1,s_2$

If the running time is linear

$t_2 = t_1\frac{s_2}{s_1} = 0.5*\frac{1000}{100} = 0.5*10 = 5s$

If the running time is quadratic

$t_2 = t_1\left(\frac{s_2}{s_1}\right)^2 = 0.5*\left(\frac{1000}{100}\right)^2 = 0.5*10^2 = 50s$

If the running time is log-linear

$t_2 = t_1\frac{log(s_2)}{log(s_1)} = 0.5*\frac{log(1000)}{log(100)} = 0.5*1.5 = 0.75s$

If the running time is cubic:

$t_2 = t_1\left(\frac{s_2}{s_1}\right)^3 = 0.5*\left(\frac{1000}{100}\right)^3 = 0.5*10^3 = 500s$

6 0

3 years ago

Please help<br> I don't even understand the question, I need help ASAP!

Iteru [2.4K]

Answer:

i think it is

divide by 10

subtract 10

subtract 18

divide by 5

Step-by-step explanation:

6 0

4 years ago

Se tiene el mismo número de cajas de manzanas que de limones. Si en una caja de manzanas caben 13 unidades y en una de limones c

sattari [20]

Answer: 6 cajas de cada tipo de fruta.

Step-by-step explanation:

En cada caja de manzanas, tenemos 13 manzanas.

En cada caja de limones, tenemos 17 limones.

Si el numero total de cajas es C, entonces el numero total de manzanas es:

C*13

y el numero total de limones es: C*17.

Si en total tenemos 180 frutas, entonces tenemos que:

C*13 + C*17 = 180

C*(13 + 17) = 180

C*30 = 180

C = 180/30 = 6

Tenemos 6 cajas de cada tipo de fruta.

7 0

3 years ago

Read 2 more answers

Prove<br>that<br>2 cos (A +45°) cos (B-45°) = cos 2A

wolverine [178]

Answer:

Step-by-step explanation:

2 cos(A+45)cos (B-45)

=2[cos A cos 45-sin A sin 45][cos B cos 45+sin B sin 45]

=2[cos A ×1/√2-sin A ×1/√2][cos B×1/√2+sin B×1/√2]

=2[1/√2(cos A-sin A)][1/√2(cos B-sin B]

=2×1/√2×1/√2 (cos A-sin A)(cos B+sin B)

=cosA cos B+cos A sin B-sin A cos B-sin A sin B

=cos A cos B-sin A sin B-(sin A cos B-cos A sin B)

=cos (A+B)-sin (A-B)

i think there should be A in place of B.

then

=cos (A+A)-sin (A-A)

=cos 2A-sin 0

=cos 2A

as sin 0=0

6 0

4 years ago