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3 years ago

What is 11mp in expanded form

Mathematics

1 answer:

Flauer [41]3 years ago

4 0

Answer:

<h3>Eleven-per miles who doesn't know that or 11.✌️</h3>

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A metal bar is 7 5/8 inches long. If 9/32 inches is cut off one end, how long is the bar after the cut?

Blizzard [7]

7 11/32 inches i do believe

8 0

3 years ago

Read 2 more answers

Given f(x) = 10 - 2x, find f(7).

Dmitry_Shevchenko [17]

Answer:

-4

Step-by-step explanation:

f(x) = 10 - 2x,

Let x= 7

f(7) = 10 2(7)

= 10-14

= -4

7 0

4 years ago

A theater has 1200 seats. each row has 20 seats. what is the equation to find the number of rows in the theater

Ugo [173]

Let be x the number of rows
there are 1200 seats, and each row has 20seats
so 20x=1200, so x= 60, there are 60 rows in the theater

6 0

4 years ago

My daughter is having a hard time trying to figure this problem.

Natalija [7]

Hey there! :-)

First, let's find the slope of the line.

We can do that by using this formula:

Slope=Rise/Run

Where

Rise=how many units we move up

Run=how many units we move left or right.

We move 5 units up and 8 units to the right.

Therefore, the slope is 5/8.

The y-intercept (where the line touches the graph) is -9/8.=

Therefore, the equation of the line is y=5/8x-9/8.

Hope this helps you daughter. Use the comment section to clarify any doubts.

Answered by

~A felicitous teen who helps others with a smile on her face

Good luck.

6 0

2 years ago

Read 2 more answers

According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var

-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}$

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.9

11.2

11.5

11.8

n=10(even)

$Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7$

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}$

Standard deviation :0.89916

8.3

,10.3

,10.5

,10.6

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5$

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2$

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range : $(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)$

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0

3 years ago