Answer:
(a) 3.75
(b) 2.00083
(c) 0.4898
Step-by-step explanation:
It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].
(a)
Compute the mean of X as follows:
(b)
Compute the variance of X as follows:
(c)
Compute the value of P(X < 3.7) as follows:
![P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898](https://tex.z-dn.net/?f=P%28X%20%3C%203.7%29%3D%5Cint%5Climits%5E%7B3.7%7D_%7B1.3%7D%7B%5Cfrac%7B1%7D%7B6.2-1.3%7D%7D%5C%2C%20dx%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B4.9%7D%5Ctimes%20%5Bx%5D%5E%7B3.7%7D_%7B1.3%7D%5C%5C%5C%5C%3D%5Cfrac%7B3.7-1.3%7D%7B4.9%7D%5C%5C%5C%5C%5Capprox%200.4898)
Thus, the value of P(X < 3.7) is 0.4898.
For this, no math is even needed! The question says 1,000 people were interviewed. 42% percent of that 1,000 owns an SUV. If it's a percent, it is 42/100, right? Now we have to make that 42/100 out of 1000. We add a zero to the 100 on the bottom (42/1000). We do the same thing on the top. Add a zero! 420.
SECOND POSSIBLE SOLUTION
Solve this with logic! 42% is nearly 50%. Half of 1,000 is 500. What is closest to 500? 420! This solution is even easier.
Hope this helps you!
Answer:
1) 2
2) 3
3) 4
4) 5
Step-by-step explanation:
Plug in the c variables in the table into the equation to find w.
Answer:
2.89 percent chance
Step-by-step explanation:
so first if you divide 9200 and 47 you get a total of 195.74 .now if you combine the weight of each passenger and crew memeber and their luggage it has a mean of 200.4 pounds with a standard deviation of 69.3 pounds so their is a 2.89 percent chance im sure if not shoe me the nswers and i will give you th correct answer
