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galina1969 [7]
3 years ago
14

Write the equation you would use to solve for x. Then solve. ​

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer:

x=12

Step-by-step explanation:

we know that the sum of the angles in a triangle is 180 degrees

to find x we have to calculate the sum of the angles

(10x-11)+(3x-2)+(3x+1)=180

10x-11+3x-2+3x+1=180

16x-12=180

16x=180+12

16x=192

x=192/16=12

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
Brrunno [24]

Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}.

The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

The area (in square inches) of a circle of radius 10 inches is:

\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

3 0
3 years ago
Which equation could have been used to create this graph?
andrew11 [14]
The answer is A hope this helps 
4 0
3 years ago
Help with the problem
KiRa [710]

Answer:

Not clear of the question

Step-by-step explanation:

  • Ueuuhdhd
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3 0
3 years ago
Whoever answers this NOW will get brainliest
gavmur [86]

Answer:

I think is -x + 105/42y

Step-by-step explanation:

2(3/10)x - 5/7y - 4(5/6)y - 2(4/5)x

6/10x - 5/7y - 20/6y - 8/5x

6/10x - 8/5x - 5/7y - 20/6y

6-16/10x - 35+140/42y

-10/10x + 105/42y

-x + 105/42y

5 0
3 years ago
What is the area of a sector with a central angle of 131 degrees and a radius of 7.2 ft?
svetoff [14.1K]

Answer:

162.78

Step-by-step explanation:

Use your π =3.14

3.14 times 7.2 times 7.2

5 0
3 years ago
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