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satela [25.4K]
3 years ago
14

PLEASE HELP WITH WORK ILL GIVE BRAINLIEST!

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0

Answer:

49°

Step-by-step explanation:

arc AB subtends a central angle of 98°

Let <em>O</em> be the center of the circle.

∠OAB = ∠OBA = (180°-98°)/2 = 41°

Assuming that BC  is tangent to the circle, ∠OBC = 90°

∠ABC = ∠OBC - ∠OBA = 90° - 41° = 49°

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Given r(x) =11/(x-4)^2 which represents a domain restriction on r(x) and the corresponding inverse function?
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Answer:x>4;r-1(x)=4-(root of (11/x))

Step-by-step explanation:

Edgenuity 2020

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Write the number in 2 equivalent forms as a fraction, decimal, or percent.
hjlf

Answer:

96% percent and fraction is 24/25

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Find the indicated angle . (Use either the Law of Sines or the Law of Cosines, as appropriate. Assume a = 16, c = 12, and ∠C = 4
mote1985 [20]
Use the law of sines
11/sin50°=13/sinθ
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2 years ago
A rectangular prism has dimensions of 2 cm by 2 cm by 5 cm.
nataly862011 [7]

Answer:

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4 0
3 years ago
Part of a university's professor's job is to publish his or her research. This task often entails reading a variety of journal a
goblinko [34]

Answer:

(18.1042, 35.2292) is a 90% confidence interval for the mean number of journal articles read monthly by professors.

Step-by-step explanation:

We have a small sample of size n = 12, \bar{x} =  26.6667 and s = 16.5163. A pivotal quantity for this case is given by T = \frac{\bar{X}-\mu}{S/\sqrt{n}} which has a t distribution with n-1 degrees of freedom if we suppose that we take the sample from the normal population. The confidence interval is given by \bar{x}\pm t_{\alpha/2}(\frac{s}{\sqrt{n}}) where t_{\alpha/2} is the \alpha/2th quantile of the t distribution with n - 1 = 12 - 1 = 11 degrees of freedom. As we want the 90% confidence interval, we have that \alpha = 0.1 and the confidence interval is 26.6667\pm t_{0.05}(\frac{16.5163}{\sqrt{12}}) where t_{0.05} is the 5th quantile of the t distribution with 11 df, i.e., t_{0.05} = -1.7959. Then, we have 26.6667\pm (-1.7959)(\frac{16.5163}{\sqrt{12}}) and the 90% confidence interval is given by (18.1042, 35.2292).

6 0
3 years ago
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