The answer would be 6 I think
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
Answer:
2√2
Step-by-step explanation:
compare this equation with the standard equation of a circle centered at (h, k) with radius r:
(x - h)^2 + (y - k)^2 = r^2
(x - 5)^2 + (y + 7)^2=8
Clearly, r^2 = (radius)^2 = 8, and so the radius, r, is √8, or 2√2
Answer:
asa
Step-by-step explanation:
right angle
same base side
same length to other angle
Answer:
make me as brain list plz
