Yes it's SAS
AD = CD (given)
BD = BD (common side )
but since it didn't say AC丄BD
it's no way to prove the angels r 90° :/
but as it already given AD= CD
so it's proven that it's an isosceles triangle
therefore
∠BAD = ∠BCD (base ∠s isos. ∆)
therefore it's SAS (side angel side)
=d/dx((t^4-6)^3) * (t^3+6)^4 + d/dx((t^3+6)^4) * (t^4-6)^3
=3*(t^4-6)^2 * (t^3+6)^4 * d/dx(t^4-6) + 4*(t^3+6)^3 * (t^4-6)^3 * d/dx(t^3+6)
=3*(t^4-6)^2 * (t^3+6)^4 * 4t^3 + 4*(t^3+6)^3 * (t^4-6)^3 * 3t^2
Simplify that if youd like
Using it's concept, it is found that the probabilities are given as follows:
a.1/2, 1/9, 5/9.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, 90 out of 180 individuals are children, hence the probability is given by:
p = 90/180 = 1/2.
Out of 90 adults, 60 - 50 = 10 preferred cheeseburgers, hence the probability is given by:
p = 10/90 = 1/9.
Of the 180 individuals, 90 are children, and 10 are adults who prefer cheeseburgers, hence the probability is given by:
p = 100/180 = 10/18 = 5/9.
Hence option a is correct.
More can be learned about probabilities at brainly.com/question/14398287
#SPJ1
Answer:
10
Step-by-step explanation:
The number of different ways that 2 lights can be chosen from 5 is ₅C₂. Use a calculator or find the value manually:
₅C₂ = 5! / (2! (5−2)!)
₅C₂ = 5! / (2! 3!)
₅C₂ = 5×4×3×2×1 / (2×1 × 3×2×1)
₅C₂ = 5×4 / 2
₅C₂ = 10
‘a’ is a variable
so this means something multiplied by 1/2 = 11
to solve we will divide both sides by 1/2 to isolate ‘a’
so a= 22
you can verify by plugging 22 into a
so
(1/2)(22)=11
which is true
