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2 years ago

What is the value of R in this circuit

Mathematics

1 answer:

goblinko [34]2 years ago

5 0

See that messy ugly fraction on the right side of the equation ? Let's make it easier to write.

If we multiply the top and bottom of the fraction by the same thing, we won't change the value of the fraction. Let's multiply top and bottom by R .

The fraction 1 / (1/R + 1/2R)

Multiply top and bottom by R :

The fraction = R / (1 + 1/2) .

But that's just R/1.5 .

So 20 = R/1.5

Multiply each side of this equation by 1.5 , and you have . . .

30 = R

This is not even a problem about electrical circuits or resistors. This is a problem about handling complicated fractions to make them less messy.

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Find the 53rd term of the arithmetic sequence 27,11, -5

vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term, that is, $d = a_{3} - a_{2} = a_{2} - a_{1}$ .

To find the nth term of the sequence, this equation can be written as:

$a_{n} = a_{1} + (n-1)d$

27,11, -5

So $a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d$

$a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805$

The 53rd term of this arithmetic sequence is -805.

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