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Gnom [1K]
2 years ago
12

How to solve (-6y^-3z^-3)(-1/2y^-1z)

Mathematics
1 answer:
Oksana_A [137]2 years ago
5 0

Answer:

        3

__________

  y ^4  z ^2

Step-by-step explanation:

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2X+15= -3x how do you work this equation​
Sphinxa [80]

Answer: x=-3

<u>Add 3x to both sides</u>

<u></u>2x+15+3x=-3x+3x\\5x+15=0<u></u>

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<u>Subtract 15 from both sides</u>

<u></u>5x+15-15=0-15\\5x=-15<u></u>

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<u>Divide both sides by 5</u>

<u></u>5x/5=-15/5\\x=-3<u></u>

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3 years ago
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3 years ago
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If you have a 5 letters A,B,C,D,E and you can put them in any order how many ways can you place them
IceJOKER [234]

The first letter can be any one of 5.  For each of those . . .
The second letter can be any one of the remaining 4.  For each of those . . .
The third letter can be any one of the remaining 3.  For each of those . . .
The fourth letter can be any one of the remaining 2.  For either of those . . .
The fifth letter is the last remaining one.

  Total number of possibilities = (5 x 4 x 3 x 2 x 1)  = 

                                                          <em> 120 ways</em> to line them up.

Now, may I say that being a hater of school is not something that
makes you cool.  Maybe it does make you one of the crowd, but life
is not a war between you and school.  School is simply something that
a lot of grown-ups spend a lot of money on, and a lot of teachers spend
their whole life on, to make sure that a lot of kids won't go through <em><u>their</u></em>
whole life stupid.  You can learn everything you ever want to know there,
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4 0
2 years ago
If i leave my house at 6:52 am and run 1 mile at an easy pace (8:15 per mile), then 3 miles at tempo (7:12 per mile) and 1 mile
FinnZ [79.3K]

Running 2 miles at 8:15 per mile takes 16:30 minutes.

Running 3 miles at 7:12 per mile takes 21:36 minutes.

The total running time is 16:30 + 21:36 = 38:06 minutes. That length of time after 6:52 am is 7:30:06 am.

You get home for breakfast at 6 seconds past 7:30 am.

8 0
3 years ago
A survey of an urban university (population of 25,450) showed that 870 of 1,100 students sampled supported a fee increase to fun
Katen [24]

Answer:

95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C

Step-by-step explanation:

The confidence interval for a proportion is given as [p +/- margin of error (E)]

p is sample proportion = 870/1,100 = 0.791

n is sample size = 1,100

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (z) at 5% significance level is 1.96.

E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024

Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767

Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815

95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.

5 0
2 years ago
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