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tatuchka [14]
3 years ago
13

Wilson began watering his garden with a watering can that was completely full. The amount of water in the can as Wilson was wate

ring can be represented by a linear function and is shown in the graph below. Which statement is correct?

Mathematics
2 answers:
givi [52]3 years ago
6 0

Answer:

Option B is correct, i.e. The amount of water originally in Wilson's can was 2.5 gallons.

Step-by-step explanation:

Given is the graph of Amount of water (in gallons) v/s Time (in seconds).

It is a linear graph whose general equation is given as follows:-

y=mx+b.

Where y = Amount of water, x = Time, m = slope, b = y-intercept (when time is zero).

Finding slope of line, m = (2.3 - 2.5)/(1 - 0) = -0.2 gallons per second.

Finding y-intercept of line, b = 2.5 gallons (at t=0).

Hence, option B is correct, i.e. The amount of water originally in Wilson's can was 2.5 gallons.

jok3333 [9.3K]3 years ago
6 0

Answer:B

Step-by-step explanation: The amount of water originally in Wilson’s can was 2.5 gallons.

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4 0
3 years ago
V= 512^2/3* 19683^1/3*256^1/4
irina1246 [14]

Answer:

V=512^2/3* 19683^1/3*256^1/4    = 6912

Step-by-step explanation:

V= (512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times  (256^{\frac{1}{4} } )\\

As

2^{9}  = 512\\2^{8} =  256\\19683^{\frac{1}{3} } = 27\\

putting values in equation

V= 2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\  let it be equation 1

As

2^9^{\frac{2}{3} }  = 2^6    according\,to\,exponential\,rule\\2^8^\frac{1}{4} =     2^2     according\,to\,exponential\,rule\\\\

putting values in equation 1

V= 2^6\times 27\times 2^2

According to exponential rule 2^6 \times 2^2 = 2^8

V=2^8 \times 27\\

V=256\times 27\\V=6912

So

V= 6912

Keywords: Algebra

Learn more about algebra at:

  • brainly.com/question/3739260
  • brainly.com/question/13168205
  • brainly.com/question/9607945

#learnwithBrainly

7 0
3 years ago
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