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Dovator [93]
3 years ago
13

The cycle time for trucks hauling concrete to a highway construction site is uniformly distributed over the interval 40 to 75 mi

nutes. What is the probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes
Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

0.8333 = 83.33% probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

Uniformly distributed over the interval 40 to 75 minutes.

This means that a = 40, b = 75

It is known that the cycle time exceeds 45 minutes

This means that we can use a = 45

What is the probability that the cycle time exceeds 50 minutes?

P(X > 50) = \frac{75 - 50}{75 - 45} = 0.8333

0.8333 = 83.33% probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes

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Can you help me with 12-3(x+1)=30
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Greetings!

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Distribute the Parenthesis.
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What is the factored for of x^2-x-2?
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The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
3 years ago
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