1.) How many hundreds are in 1,000?

Mathematics

2 answers:

Solnce55 [7]2 years ago

5 0

1) b. There are 10 100's in 1,000
2) c. This is what it is written in words

zhuklara [117]2 years ago

5 0

1) this is a basic division problem. To start off, do how many 100s go into 100, which equals one. Now 1000 has one more zero than 100, so you must go up one place for the 1000, meaning you go up to the next place on the answer as well. So it is B

2) basically, you need to get which is each place. The 8 is 8 million, the 2 is 200 thousand, th 54 is 54 thousand, and the 060 is 60, so you badically put them altogether. So the answer is C.

Hope this helps :D

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Show that if f(n) is O(g(n)) and d(n) is O(h(n)) then f(n) + d(n) is O(g(n) + h(n)).

GaryK [48]

$f(n)\in\mathcal O(g(n))$ is to say

$|f(n)|\le M_1|g(n)|$

for all $n$ beyond some fixed $n_1$ .

Similarly, $d(n)\in\mathcal O(h(n))$ is to say

$|d(n)|\le M_2|h(n)|$

for all $n\ge n_2$ .

From this we can gather that

$|f(n)+d(n)|\le|f(n)|+|d(n)|\le M_1|g(n)|+M_2|h(n)|\le M(|g(n)|+|h(n)|)$

where $M$ is the larger of the two values $M_1$ and $M_2$ , or $M=\max\{M_1,M_2\}$ . Then the last term is bounded above by

$M(|g(n)|+|h(n)|)\le2M\max\{|g(n)|,|h(n)|\}$

from which it follows that

$f(n)+d(n)\in\mathcal O(\max\{g(n),h(n)\})$

3 0

2 years ago

Can someone help me with this one? Thank you.

Andreas93 [3]

Step-by-step explanation:

I haven't used distance formula or Pythagoras theorem, not sure why that's given at the bottom of your question. check the image. that is how I solved it