The true statement is that only line A is a well-placed line of best fit
<h3>How to determine the true statement?</h3>
The scatter plots are not given. However, the question can still be answered
The features of the given lines of best fits are:
<u>Line A</u>
- 12 points in total
- Negative correlation
- Passes through the 12 points with 6 on either sides
<u>Line B</u>
- 12 points in total
- Positive correlation
- Passes through the 12 points with 8 and 4 in either sides
For a line of best fit to be well-placed, the line must divide the points on the scatter plot equally.
From the given features, we can see that line A can be considered as a good line of best fit, because it divides the points on the scatter plot equally.
Read more about line of best fit at:
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<span>the probability that a pen from the first box is selected
= total number of pens in 1st box/total number of objects in box 1
= 5/12
</span>the probability that a crayon from the second box is selected
= total number of crayons in 2nd box/total number of objects in box 2
= 6/8 = 3/4
On the 7th, Andi had $48 in her account. We want to find when she had $92 less than what she had on the 7th.
First, let's find out how much $92 less is:
48 - 92 = -44
We are looking for when Andi had $-44 in her account. Looking at the number line, the day Andi had $-44 in her account was on the 14th.
The correct answer is C. The 14th.
Hope this helps!! :)
Step-by-step explanation:
Consider the provided information.
For the proportion method first set up the equation like this:

Perform the cross multiplication and then solve for the missing part.
For example:
Find 80 percentage of 10.
Step 1: Set up the equation.


Step 2: Perform the cross multiplication

Step 3: Solve for the missing part.


Answer:
2.5 hours
Step-by-step explanation:
The product of speed and time is distance. If the distance is the same, then time is inversely proportional to speed. At 60/50 = 6/5 times the speed, the return trip will take 5/6 times the time:
(5/6)(3 hours) = 2.5 hours . . . time for return trip