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slavikrds [6]
3 years ago
6

1.) How many hundreds are in 1,000?

Mathematics
2 answers:
Solnce55 [7]3 years ago
5 0
1) b. There are 10 100's in 1,000
2) c. This is what it is written in words
zhuklara [117]3 years ago
5 0
1) this is a basic division problem. To start off, do how many 100s go into 100, which equals one. Now 1000 has one more zero than 100, so you must go up one place for the 1000, meaning you go up to the next place on the answer as well. So it is B

2) basically, you need to get which is each place. The 8 is 8 million, the 2 is 200 thousand, th 54 is 54 thousand, and the 060 is 60, so you badically put them altogether. So the answer is C.

Hope this helps :D
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Determine the future value of a $25000 investment at an annual rate of 4.85% compounded quarterly for 6 years.
Nutka1998 [239]
 = $ 32,275.00

Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 4.85%/100 = 0.0485 per year,
putting time into years for simplicity,
24 quarters ÷ 4 quarters/year = 6 years,
then, solving our equation

A = 25000(1 + (0.0485 × 6)) = 32275 
A = $ 32,275.00

The total amount accrued, principal plus interest,
from simple interest on a principal of $ 25,000.00
at a rate of 4.85% per year
for 6 years (24 quarters) is $ 32,275.00.
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Step-by-step explanation:

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Answer:

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3 years ago
In a rational function, is the horizontal shift represented by the vertical asymptote?
ziro4ka [17]
<h3>Short Answer: Yes, the horizontal shift is represented by the vertical asymptote</h3>

A bit of further explanation:

The parent function is y = 1/x which is a hyperbola that has a vertical asymptote overlapping the y axis perfectly. Its vertical asymptote is x = 0 as we cannot divide by zero. If x = 0 then 1/0 is undefined.

Shifting the function h units to the right (h is some positive number), then we end up with 1/(x-h) and we see that x = h leads to the denominator being zero. So the vertical asymptote is x = h

For example, if we shifted the parent function 2 units to the right then we have 1/x turn into 1/(x-2). The vertical asymptote goes from x = 0 to x = 2. This shows how the vertical asymptote is very closely related to the horizontal shifting.

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