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aleksklad [387]
3 years ago
15

Find the value of x

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

35.8 deg

Step-by-step explanation:

a/sin A = b/sin B

24/sin x = 39/sin 71.8

sin x = (24 * sin 71.8)/39

sin x = 0.584598

x = sin^-1 0.584598

x = 35.8 deg

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Lubov Fominskaja [6]

Answer:

a: 130

b: 130

c: 50

Step-by-step explanation:

a straight line has an angle of 180, so those two angles are going to add up to 180. and opposite angles are equivalent

6 0
3 years ago
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5.7y-5.2=y/2.5 how to solve
11Alexandr11 [23.1K]

5.7y-5.2=y/2.5

Add 5.2 to both sides:

5.7y = y/2.5 + 5.2

y/2.5 = 0.4y

5.7y = 0.4y + 5.2

Subtract 0.4y from both sides:

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Is math hard or easy!<br> comment down below
levacccp [35]
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3 years ago
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What is the distance between (4, 7)(4,7)left parenthesis, 4, comma, 7, right parenthesis and (2, 2)(2,2)left parenthesis, 2, com
tester [92]

Answer: square root of 29

Step-by-step explanation:

Given the question :

Distance between (4, 7) and (2, 2)

Distance between two points is given by:

Distance = sqrt[(X2 - X1)² + (Y2 - Y1)²]

X1 = 4 ; Y1 = 7 ; X2 = 2 ; Y2 = 2

Distance = sqrt[(2 - 4)² + (2 - 7)²]

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7 0
3 years ago
Problem PageQuestion Working together, two pumps can drain a certain pool in hours. If it takes the older pump hours to drain th
gizmo_the_mogwai [7]

Answer:

10.5 hours.

Step-by-step explanation:

Please consider the complete question.

Working together, two pumps can drain a certain pool in  6  hours. If it takes the older pump  14  hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own?

Let t represent time taken by newer pump in hours to drain the pool on its own.

So part of pool drained by newer pump in one hour would be \frac{1}{t}.

We have been given that it takes the older pump 14 hours to drain the pool by itself, so part of pool drained by older pump in one hour would be \frac{1}{14}.

Part of pool drained by both pumps working together in one hour would be \frac{1}{6}.

Now, we will equate the sum of part of pool emptied by both pumps with  \frac{1}{6} and solve for t as:

\frac{1}{14}+\frac{1}{t}=\frac{1}{6}

\frac{1}{14}\times 42t+\frac{1}{t}\times 42t=\frac{1}{6}\times 42t

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\frac{4t}{4}=\frac{42}{4}

t=10.5

Therefore, it will take 10.5 hours for the newer pump to drain the pool on its own.

6 0
3 years ago
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