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koban [17]
3 years ago
6

Which property, definition,

Mathematics
1 answer:
Elodia [21]3 years ago
5 0
Is it definition of Congruence?
You might be interested in
An electrician charges a $100 flat fee, plus $75 per hour to work on a house.
jek_recluse [69]

Answer:

y=75x+100

Step-by-step explanation:

8 0
2 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
Is y=2x+3 a proportional relationship
lisabon 2012 [21]

answer:

no, it does not represent a proportional relationship because it has a y-intercept therefore it won’t go through the origin.

4 0
3 years ago
Read 2 more answers
SOMEONE PLZ HELP ME WITH 10 and 8!!!!!
Allisa [31]

Answer:

10.23.75^{o}

8. 34.76^{o}

Step-by-step explanation:

10. each step is 36, so i added it twice to get 72.

     then add 16 twice = 32

      this gives us two sides to our triangle.

      We can now use tan since we know opp and adj

      tan 32/72 = .44

      arctan = 23.75

8. since we again know the opposite and adjacent sides to the angle e are trying to find we can use tan again.

  tan 12.5/18 = .694

  arctan= 34.76

5 0
3 years ago
Write two ratios equivalent to 24 : 9.
notsponge [240]

Answer:

8:3

16:6

Step-by-step explanation:

First, let's check if 9 and 24 have any common factor. If they do have any common ones, we must find the GCF (greatest common factor).

Factors of 9: 1, 3, 9

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The common factors both of the numbers share and 1 and 3. To find the GCF, simply compare one of the factors to the other.

1 < 3

Now that we know the GCF, we can divide the two numbers in the ratio 24 : 9 by it (3).

24:9

24/3:9/3

<u>8:3</u>

Now that our ratio is simplified, it's going to be much easier to find more ratios that are equivalent. <u>8:3</u> is already one equivalent ratio, but if we multiply each number in the ratio by any other number, we can get a new equivalent ratio. Let's multiply each number in the ratio by 2:

<u>8:3</u>

8 ⋅ 2:3 ⋅ 2

<u>16:6</u>

<u></u>

So, another equivalent ratio to 24:9 (and <u>8:3</u>) is <u>16:6</u>.

3 0
3 years ago
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