All categories

2 years ago

Help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

podryga [215]2 years ago

3 0

Step-by-step explanation:

and and get some tonight at work today but it will take him home to a and then you can see to do with me for a bit of the time and

You might be interested in

What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i?

astra-53 [7]

x³ - 3x² + 4x - 2

complex roots occur in conjugate pairs

1 + i is a root then so is 1 - i

the factors of the polynomial are therefore

f(x) = (x - 1 )(x - (1 + i))(x - (1 - i))

= (x - 1 )(x² - 2x + 2 ) ( expand factors and simplify )

= x³ - 3x² + 4x - 2

4 0

2 years ago

Read 2 more answers

E: f= 3:7<br> f:g= 2:3<br> Work out e:g<br><br> Give your answer in its simplest form.

Alisiya [41]

Answer:

what?

Step-by-step explanation:

...............

5 0

2 years ago

Read 2 more answers

If you have $15000 and you earn 10% simple interest per year on it for 10 months how much will you have?

zubka84 [21]

You would have $165,000, hope this helps

7 0

2 years ago

A surgical technique is performed on eleven patients. You are told there is 90% chance of success. Find the probability that the

Alexandra [31]

Answer:

Your answer is : 0.7748

Step-by-step explanation:

Use bernoulli probability

3 0

2 years ago

Based on a poll, 60% of adults believe in reincarnation. Assume that 5 adults are randomly selected, and find the indicated p

vlabodo [156]

Answer:

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they believe in reincarnation, or they do not believe. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 5 adults, so $n = 5$

60% believe in reincarnation, so $p = 0.6$

What is the probability that exactly 4 of the selected adults believe in reincarnation?

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

3 0

2 years ago