So, first lets define our variables:
let x = the number of dimes
let y = the number of nickels
so our first equation would be x+y = 16
Since dimes are 10 cents and nickels are 5 cents the next equation would be as follows:
.10x+.05y = 1.35
now change the first equation so y = -x+16
now substitute:
.10x+.05(-x+16) = 1.35
then multiply so you get .10x+-.05x+0.8=1.35
combine like terms and you get .05x+0.8 = 1.35
then subtract 0.8 from both sides and you get .05x = 0.55 then subtract
and you get x = 11 then substitute 11 for where x should be and you should get y = 5
So, you have 11 dimes and 5 nickels
Answer:
the correct answer is c 90 days just took the test
Step-by-step explanation:
Answer:
y = 7x + 4? - 7 7
Step-by-step explanation:
the denominator cannot be zero, because the division by zero is not defined, therefore:
![\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2-9%3D0%20%5C%5C%20%5Ctext%7BSolving%20for%20x%3A%7D%20%5C%5C%20x%5E2%3D9%20%5C%5C%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Csqrt%5B%5D%7B9%7D%20%5C%5C%20x%3D%5Cpm3%20%5Cend%7Bgathered%7D)
Therefore the domain of (f o g)(x) is:
