Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Circumference one = (2R)*pi let that value be 2x
C second = 5x = (2R)*pi * 5 / 2 = (5R)*pi
So Radius one / Radius two = 2 / 5
Area1:Area2=pi(2R)^2:pi(5R)^2=pi(4R^2):pi(25R^2), pi cancel out we get
4R^2:25R^2, now R^2 cancel out and we get ratio of
4:25
Answer:
y = 5/4 (x) + 7
Explanation:
Slope of a line (m): (y₂ - y₁) ÷ (x₂ - x₁)
Slope: (2 - -3) ÷ (-4 - -8) = 5 ÷ 4 = 5/4
Point slope form: y - y₁ = m (x - x₁)
Equation: y - 2 = 5/4 (x - -4)
distribute the 5/4
y - 2 = 5/4 (x) + 5
add 2 to both sides
y = 5/4 (x) + 7
I hope this helps!
Answer:
Step-by-step explanation:
x^2 - 4x + 20 = 0
x^2 - 4x = -20
x^2 = 4x - 20
x = 2x - 4.47
-3x = -4.47
x = roughly 1.5
A because a colored circle means it’s greater than