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tigry1 [53]
2 years ago
11

Find the slope intercept form of the line slope : 0 ordered pair : (5,5)

Mathematics
2 answers:
zysi [14]2 years ago
5 0
Given:
O(0,0)
P(5,5)
solution:
slope=(5-0)/(5-0)=1
use point-slope form:
y-y1=m(x-x1)
y-5=1(x-5)
y-5=x-5
y=x+0
where 1 is the slope, 0 is the y-intercept
the final form simplifies to
y=x

dolphi86 [110]2 years ago
3 0
Check the picture below

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What is the value of x?
Inessa05 [86]
3x-14=4x-9
-4x     -4x
-x-14=-9
   -14  -14
-x=-15
-x/-1=-15/-1
x=15
Sorry if this is a bit confusing, but I hope I helped
5 0
3 years ago
A tire manufacturer is considering a newly designed tread pattern for its all-weather tires. Tests have indicated that these tir
Nataly_w [17]

Answer:

With outlier (102)

t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415      

p_v =P(t_{9}>0.415)=0.344    

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.    

Without outlier (102)

t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285      

p_v =P(t_{8}>3.285)=0.0056  

And we conclude that we reject the null hypothesis since p_v. So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier, removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Data: 129, 128, 130, 132, 135, 123, 102, 125, 128, 130

We can calculate the mean with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=126.2 represent the sample mean    

s=9.138 represent the sample standard deviation  

n=10 represent the sample selected  

\alpha significance level    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is significantly higher than 125, the system of hypothesis would be:    

Null hypothesis:\mu \leq 125    

Alternative hypothesis:\mu > 125    

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{126.2-125}{\frac{9.138}{\sqrt{10}}}=0.415      

P-value  

First we need to calculate the degrees of freedom given by:

df=n-1=10-1= 9

Then since is a right tailed sided test the p value would be:    

p_v =P(t_{9}>0.415)=0.344    

Conclusion    

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 125 feet at 5% of significance.    

Using all the data we see that we don;t have enough info to conclude that the true mean is higher than 125, but if we see careful 9 of the 10 values are over the limit of 125 feet. And if we repeat the procedure with the outlier of 102. We got this:

\bar X=128.89 represent the sample mean    

s=3.551 represent the sample standard deviation

t=\frac{128.89-125}{\frac{3.551}{\sqrt{9}}}=3.285      

First we need to calculate the degrees of freedom given by:

df=n-1=9-1= 8

Then since is a right tailed sided test the p value would be:    

p_v =P(t_{8}>3.285)=0.0056  

And we conclude that we reject the null hypothesis since p_v. So the final conclusion would be not use the method since the value of 102 observed can be a potential outlier removing this value we see that we reject the null hypothesis and we have a significant result that the true mean is higher than 125.

8 0
3 years ago
Which expression is equivalent to (2x-5)-5x(x-4)
Murrr4er [49]
2x-5-5x²+20x
-5x+22x-5
7 0
3 years ago
Can someone please answer this​
bija089 [108]

Answer:

the area is 20 in

Step-by-step explanation:

3 times 4 is 12. since we used 3 inches out of the 11, we can only multiply the 8 inches with 1. 8 times 1 is 8. 12+8=20.

6 0
2 years ago
What is the converse of the given conditional statement?
Paha777 [63]
The converse of an if statement is a statement in which the hypothesis and conclusion are switched.

<span>You will get into college if you work hard.

The "if" part is the hypothesis.
The "then" part is the conclusion.

Rewrite the original if statement in the if-then form:

If you work hard, then you will get into college.

The hypothesis is the if part: "you work hard"
The conclusion is the then part: "you will get into college"

To write the converse, switch the hypothesis and the conclusion.

If you get into college, then you worked hard.

This happens to be choice A.
</span>
7 0
2 years ago
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