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3 years ago

Y = 5x -4x + 3y = -11

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Pretty sure it’s 6.......

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Suceción numerica 265 250 235 220 ____ ____ 175 ____ 145 130 ____ ____ ____ y aqui otra 4 12 36 ____ ____ ____ 2916 8748 ____ __

alina1380 [7]

Respuesta:

A la primera le vas a quitar 15 con cada número. A la segunda, todo lo multiplicas por 3 cada vez que vas avanzando.

265, 250 . . . 220, 205, 190, 175, 160, 145, 130, 115, 100, 185. ---------- 4, 12, 36, 108, 324, 972, 2,916, 8,748, 26,244, 78,732. ---------- 5, 20, 15, 40, 25, 60, 35, 80, 45, 90, 55, 100, 65, 110, 75. ---------- 30, 90, 270, 810, 2,430, 7,290, 21,870, 65,610, 196,830. ---------- 703125, 140625, 28125, 5625, 1125, 225, 45, 9. ---------- 36864, 9216, 2304, 576, 144, 36, 9, 2.25.

8 0

3 years ago

a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface

Shtirlitz [24]

Answer:

The location will be at $- 28\frac{1}{8}$ units.

Step-by-step explanation:

A scuba diver descended at a rate of $2\frac{1}{4}$ units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after $12\frac{1}{2}$ seconds the location of the diver will be given by the followings :

In one second the diver descends by 2.25 units depth.

So, in 12.5 seconds the diver will descend by $(2.25 \times 12.5) = 28.125$ units i.e. $28\frac{1}{8}$ units depth.

Therefore, the location will be at $- 28\frac{1}{8}$ units. (Answer)

6 0

3 years ago

What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?

andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5) and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)

To Find:

M(x₄ ,y₄) = ? and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

$Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})$

As M is the mid point of PR and N is the mid point of RQ so we will have

$Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})$

$Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})$

Substituting the given value in above equation we get

$Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})$

∴ $Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})$

∴ $Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)$

Similarly,

$Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})$

∴ $Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})$

∴ $Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)$

∴ M(x₄ ,y₄) = (-3.5 , 0.5) and

N (x₅ ,y₅) = ( -1 , -0.5 )

3 0

3 years ago

In a village, there was an epidemic and the population decreased by 10%. If there were only 1800 people left in the village, wha

tester [92]

$\bold{\boxed{\huge{\blue{\underline{Answer }}}}}$

$\bold{\underline{ Given :- }}$

$\sf{The\: population\: is\: decreased \:by\: 10 percent }$

$\sf{There\: were \: only \: 1800 \: people \: left}$

$\bold{\underline{ To\: Find :- }}$

$\sf{we \: have \: to \: find\: original \: population? }$

$\bold{\underline{ Let's \: Begin :- }}$

$\sf{Let \: the \: total \: population\: be \: x }$

$\sf{\underline{ Therefore }}$

$\sf{According \: to \: the \: question }$

$\sf{ x - 10/100 = 1800 }$

$\sf{ 100x - 10/100 = 1800}$

$\sf{ 100x - 10 = 1800 × 100}$

$\sf{100x - 10 = 180000}$

$\sf{ 100x = 180000 + 10}$

$\sf{ x = 180010/100}$

$\sf{ x = 1800.1 }$

$\bold{\pink{Hence , The\: original \:population \:of \: the\: village \:is \:1800.1 }}$

7 0

2 years ago

Mrs ray is teaching a 5th grade class . She is standing 5 meters in front of Kiara. Ian is sitting 12 meters directly to Kiara’a

Kaylis [27]

The answer is going to be b

8 0

2 years ago