Answer:
Tickets sold:
VIP 
$17 tickets 
$21 tickets 
Step-by-step explanation:
Let x be the number of VIP tickets.
If ten times as many $17 tickets were sold as VIP tickets, then the number of $17 tickets is
If the number of $17 tickets sold was 57 more than the sum of the number of $21 tickets and VIP tickets, then
and the number y of $21 tickets is 
Amounts earned:
VIP tickets 
$17 tickets 
$21 tickets 
Total 
The sales of all three kinds of tickets would total $51,471, so

Tickets sold:
VIP 
$17 tickets 
$21 tickets 
Answer:
Step-by-step explanation:
Answer:
16.7%.
Step-by-step explanation:
There are initially
pencils in the bag.
Take a pencil out of this bag of 47 pencils. 15 out of the 47 pencils blue. Let
represent the event of getting a blue pencil on the first pick. The probability of getting a blue pencil is:
.
There are now
pencils left in the bag. However, given that the first pencil removed from the bag is blue, the number of red pencils in the bag will still be 24. Take another pencil out of this bag of 46 pencils. Let
represent the event of getting a red pencil on the second pick. The possibility that the second pencil is red given that the first pencil is blue will be:
.
The question is asking for the possibility that the first pencil is blue and the second pencil is red. That is:
.
84j is the equivalent.
Just add 36 to 48 and put the j on.