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riadik2000 [5.3K]
3 years ago
6

The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of

18 feet and an area of 477 ft squared, find the length of the longer base.
Mathematics
1 answer:
love history [14]3 years ago
5 0
Area of a trapezoid: [(top +bottom)*height]/2
suppose the length of one base is x, then the other base is 5x-19
[(x+5x-19)*18]/2=477
[6x-19]*18=954
6x-19=53
6x=72
x=12
The longer base is 5*12-19=41


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You want to estimate the number of students in your middle school school who buy school lunch. Which sample is unbiased?
Nezavi [6.7K]
A biased example: Asking students who are in line to buy lunch 

An unbiased example: Asking students who are leaving/going to lunch(<em>NOT buying </em><em>lunch</em><em />).

But in this case, the answer choices can be... confusing.
Don't panic! You're given numbers and, of course, your use of logic.

Answer choice A: 100 students grades 6-8
Answer choice B: 20-30 students any <em>one</em> grade<em></em><em>
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An unbiased example would be to choose students from <em>any grade.</em> So we can eliminate choices B and D.

Now, the question wants to <em>estimate how many people at your middle school buy lunch.</em> This includes the whole entire school, and if you are going to be asking people, you aren't just going to assume that if 5 people out of 5 people you asked bought lunch, the whole school buys lunch.

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6 0
3 years ago
Passes through the points (−4, 2) and (12, 6)?
svlad2 [7]

<u>I'll assume you need to find the equation of the line that passes through those points.</u>

Answer:

\displaystyle y-2=\frac{1}{4}(x+4)

Step-by-step explanation:

<u>Equation of a Line:</u>

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The given points are (-4,2) and (12,6), thus:

\displaystyle y-2=\frac{6-2}{12+4}(x+4)

Operating:

\displaystyle y-2=\frac{4}{16}(x+4)

Simplifying, the equation in point-slope form is:

\mathbf{\displaystyle y-2=\frac{1}{4}(x+4)}

3 0
3 years ago
Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.
lilavasa [31]

Answer:

y = -13x + 55

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perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

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sub them into the formula,

3 = -13 (4) + c

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55 = c

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now we rewrite again the c and the m to become a complete equation : y = -13x + 55

5 0
3 years ago
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Answer:

parallel: -1

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Step-by-step explanation:

6 0
3 years ago
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