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Elodia [21]
3 years ago
14

Find the total cost uing each unit 5 ft at $3 per foot

Mathematics
1 answer:
faltersainse [42]3 years ago
3 0
The answer to u r question is 15 dollars
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What is 8.7495980 rounded to the hundreds
devlian [24]

Answer:

8.75

Step-by-step explanation:

Because the thousandths place is over five, you round up to the next number (:

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1.<br> AOGDA<br> CRP<br> PCR<br> RPC<br> PRC
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prc

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3 years ago
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Ralph has a balance of $1350 on his credit card, which he plans to pay off by making a payment of the same amount each month. Wh
Mamont248 [21]

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The answer is 40$ because 40$ makes the most sense in this particular equation

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7 0
3 years ago
Construc t a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight
GrogVix [38]

The 95% confidence interval for the population standard deviation will be,

$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\

simplifying the equation, we get

$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288

The 95% confidence interval exists (9.887, 21.288).

<h3>What is the  95% of confidence interval?</h3>

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, $n=15, \bar{X}=165.2, s=13.5$

where n exists the sample size, $\bar{X}$ exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be $\alpha=0.05$.

The 95% confidence interval for the population standard deviation will be,

$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\

substitute the values in the above equation, we get

$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\

$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\

simplifying the above equation, we get

$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288

The 95% confidence interval exists (9.887, 21.288).

To learn more about confidence interval refer to:

brainly.com/question/14825274

#SPJ4

6 0
2 years ago
Describe , Ella has 50 stacks of ten pennies in each stack.describe how to find how many pennies Ella has in all. For a 7 year o
Alex777 [14]
The Formula:Number of stacks multiplied by number of pennies in each stack
So 50x10=500
and talking money wise he has 5 dollars

6 0
3 years ago
Read 2 more answers
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