9514 1404 393
Answer:
6(a -2)(7a +2)
Step-by-step explanation:
Removing a common factor of 6 can make the quadratic factors easier to find.
= 6(7a^2 -12a -4)
We want to find factors of (7)(-4) that have a total of -12. It doesn't take much search to see they are (-14)(2), so the expression can be written as ...
= 6(7a^2 -14a +2a -4) = 6((7a^2 -14a) +(2a -4)) . . . . rewrite 'a' term; group pairs
= 6((7a(a -2) +2(a -2)) . . . . factor pair groups
= 6(a -2)(7a +2) . . . . . . . . finish factoring
