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elixir [45]
3 years ago
13

3. If x2 + 4 = 29, then x2 - 4 = ? A. 5 B. 121 C. 21 D. 25 E. 33

Mathematics
2 answers:
EastWind [94]3 years ago
7 0
Answer is c as x is 25/2
zvonat [6]3 years ago
6 0

Answer:

c

Step-by-step explanation:

<h3>because x²+4=29 you can solve the equation for x²</h3><h3>x²+4=29</h3><h3>x²=25</h3><h3>substitute the value of x² into the expression x²-4 to calculate the value the expression is equal to </h3><h3>x²-4=25-4=21</h3><h3>c.21 is your answer </h3><h3>hope this works</h3>
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If I'm 16 years old, how many months, days, hours, minutes, and seconds old am I?
irakobra [83]
16*12=months
16*365=days
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8 0
3 years ago
What is the slope of the linear model x 1 2 3 4 5 6 7 y 12 12 9 10 6 8 6
tigry1 [53]
Sorry that is not a linear model. There is not a constant rate of change. Are you sure you copied it correctly
7 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
Does anyone know the answers to I-ready ( Math Lvl F: Understanding Algerbretic Expressions)
sergij07 [2.7K]

Answer:

B 10x+5

Step-by-step explanation:

:)

5 0
3 years ago
What is an equation in point-slope form for the line perpendicular to y = 7x + 14 that contains (3, –7)?
umka21 [38]

The equation of the perpendicular line is y + 7 = -1/7(x - 3)

<h3>How to determine the line equation?</h3>

The equation is given as

y = 7x + 14

Also, from the question

The point is given as

Point = (3, -7)

The equation of a line can be represented as

y = mx + c

Where

Slope = m

By comparing the equations, we have the following

m = 7

This means that the slope of y = 7x + 14  is 7

So, we have

m = 7

The slopes of perpendicular lines are opposite reciprocals

This means that the slope of the other line is -1/7

The equation of the perpendicular lines is then calculated as

y = m(x - x₁) +y₁

Where

m = -1/7

(x₁, y₁) = (3, -7)

So, we have

y = -1/7(x - 3) - 7

Evaluate

y = -1/7(x - 3) - 7

Add 7 to both sides

y + 7 = -1/7(x - 3)

Hence, the perpendicular line has an equation of y + 7 = -1/7(x - 3)

Read more about linear equations at

brainly.com/question/4074386

#SPJ1

8 0
1 year ago
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