Let's call the three numbers x, y, and z.
The numbers are 3, 12, and 5.
x + y + z = 20
y = 4x
x + z = 8
We can rewrite the first equation because y is 4x, so
x + 4x + z = 20
5x + z = 20
And now we can use simultaneous equation rules to solve
5x + z = 20
x + z = 8
5x + z = 20
5x + 5z = 40
(subtract)
-4z + -20
÷ -4
z = 5
x + z = 8
x + 5 = 8
x = 3
y = 4x
y = 4 × 3
y = 12
I hope this helps!
Answer:
(1,0)
Step-by-step explanation:
3x + 6y = 3
7x + 3y = 7
Multiply the second equation by -2
-2( 7x + 3y = 7)
-14x -6y = -14
Add this to the first equation to eliminate y
3x + 6y = 3
-14x -6y = -14
--------------------
-11 x = -11
Divide by -11
x = 1
Now find y
3x + 6y = 3
3 +6y = 3
Subtract 3 from each side
6y = 0
y =0
Answer:
............................
Step-by-step explanation:
Huh? there can't be 4 zeroes. but if u mean 140,000,000,000; then it's 140 billion.
it u mean 14,000,000,000; then that's 14 billion.
