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1 year ago

Which inequality is true? 1.5 greater-than 2 and one-half

Mathematics

1 answer:

Travka [436]1 year ago

7 0

The inequality negative 3 and one-half greater-than negative 4.5 or -3.5 > -4.5 is true.

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have inequalities given:

$1.5 > 2\dfrac{1}{2}$

1.5 > 2.5 (false)

1/2 > 0.5

0.5 > 0.5 (false)

-2.5 > -1.5 (false)

$-3 \dfrac{1}{2} > -4.5$

-3.5 > -4.5 (true)

Thus, the inequality negative 3 and one-half greater-than negative 4.5 or -3.5 > -4.5 is true.

Learn more about the inequality here:

brainly.com/question/19491153

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Eliza started her savings account with $100. Each month she deposits $25 into her account. Determine the average rate of change

Afina-wow [57]

First, lets create a equation for our situation. Let $x$ be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span> $f(x)=25x+100$
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is: $\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1} }$ . So lets replace the values in our formula to find the average of our function:
$\frac{25(10)+100-[25(2)+100]}{10-2}$
$\frac{350-150}{8}$
$\frac{200}{8}$
$25$

We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>

6 0

3 years ago

If 2x-4= -x+5, then find the value of x

Ganezh [65]

Answer:

Step-by-step explanation:

x=3

7 0

3 years ago

PLEASE HELP AND SHOW WORK!!

Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0

2 years ago

Glen is planting square flower gardens surrounding a triangular fishpond as shown. If the sides of the triangular fishpond are 5

weqwewe [10]

Answer:

$h=\sqrt{106} \approx 10.3$ feet

Step-by-step explanation:

We will use the Pythagorean Theorem to solve this. Which states that:

One Length^2 + Another Length^2 = Hypotenuse^2

We can take one length as 5 ft and another length as 9 ft and we call the hypotenuse "h", so we have:

$5^2+9^2=h^2$

Now, let us solve for "h":

$5^2+9^2=h^2\\25 + 81 = h^2\\106=h^2\\h=\sqrt{106} \approx 10.3$

The pond's hypotenuse is about 10.3 feet

3 0

3 years ago

Practice 2- digits subtraction 50-18

timofeeve [1]

If you're asking what 50 minus 18 is, it's 32.

5 0

2 years ago

Read 2 more answers