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podryga [215]
2 years ago
5

A area of a rectangle is 52 square meters. the width is 4 meters. what would the length be ?

Mathematics
2 answers:
valina [46]2 years ago
6 0

Answer: The length would be 13 meters.

Step-by-step explanation:

Area = L*W

52 = 4L

52/4 = L

13 = L

n200080 [17]2 years ago
4 0

Answer: 13 metres.

Step-by-step explanation:

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You were just hired as an apprentice architect. Your starting salary is $68,000 annually. What is your semimonthly salary
Vikki [24]
Annual = $68,000
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8 0
3 years ago
In PQRS, PR and QS intersect at T. What additional information is needed to conclude that PQRS is a rectangle
lora16 [44]
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5 0
3 years ago
What is the set of all solutions to the equation \sqrt{x + 2}= {-x} x+2 ​ =−xsquare root of, x, plus, 2, end square root, equals
NARA [144]

Answer:

x = 2 or x = -1

Step-by-step explanation:

Given

\sqrt{x + 2}= {-x}

Required

Find the possible values fo x

\sqrt{x + 2}= {-x}

Square both sides

( \sqrt{x + 2})^2= ({-x})^2

x + 2 = x^2

Equate to 0

x^2 - x - 2 = 0

Expand

x^2 + x -2x - 2 = 0

Factorize:

x(x + 1) - 2(x + 1) = 0

(x -2)(x +1) = 0

Split:

x - 2 = 0 or x + 1 = 0

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3 0
3 years ago
If x=5, evaluate x^5 * x^-3
Artyom0805 [142]

Answer: 25

Step-by-step explanation:

Plug in x to the expression.

5^5 * 5^{-3}\\

When there is the same base of exponents is being multiplied the exponents add together and the base stays the same.

So this simplifies to, 5^2.

This then solves to 25.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=2151%20%2B%202551" id="TexFormula1" title="2151 + 2551" alt="2151 + 2551" align="absmiddle" cl
vichka [17]
This is 4702 hope it helps
6 0
3 years ago
Read 2 more answers
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