Answer:
x = 10
Step-by-step explanation:
m∠KNL = 90
10x - 10 = 90
10x = 100
x = 10
<h3>
Question: </h3><h3>
In the diagram below of Δ ABC, side BC is extended to point D, m∠A = x , m∠B = 2x+15, and m∠ACD = 5x+5 , what is m∠B ?</h3>
Answer: 3) m∠B = 25º
Step-by-step explanation:
Since m∠C is supplementary to m∠ACD
m∠C = 180º - m∠ACD
m∠C = 180º -(5·x + 5)
m∠C = 180º -5 -5·x
m∠C = 175º - 5·x
The sum of the angles of a triangle = 180º
m∠A + m∠B + m∠C = 180º
x + 2·x + 15º + 175º - 5·x = 180º
3·x - 5·x +190º = 180º
-2·x = 180º - 190º
-2·x = -10º
x = -10º/-2 = 5º
Now we can substitute this value of x in m∠B
m∠B = 2x+15
m∠B = 2·x + 15º = 2·5º + 15º = 10º + 15º = 25º
Answer: 3) m∠B = 25º
<h2><em>Spymore</em></h2>
Wait I think I learned this hold on I’ll be back with you imma read the equation
3x + 3y + 2z = -5 ⇒ 3x + 3y + 2z = -5 ⇒ 3x + 3y + 2z = -5
1x + 1y + 3z = -4 ⇒ 1x + 1y + 3z = -4 ⇒ 3x + 3y + 9z = -12
3x - 1y + 5z = -8 -7z = 7
-7 -7
z = -1
3x + 3y + 2z = -5
1x + 1y + 3z = -4 ⇒ 1x + 1y + 3z = -4
3x - 1y + 5z = -8 ⇒ 3x - 1y + 5z = -8
4x + 8z = -12
4x + 8z = -12
4x + 8(-1) = -12
4x - 8 = -12
+ 8 + 8
4x = -4
4 4
x = -1
3x + 3y + 2z = -5
3(-1) + 3y + 2(-1) = -5
-3 + 3y - 2 = -5
3y - 3 - 2 = -5
3y - 5 = -5
+ 5 + 5
3y = 0
3 3
(x, y, z) = (-1, 0, -1)
Answer:
Step-by-step explanation:
Given that the difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32.
H0: difference inmeans =0
Ha: difference inmeans not equal to 0
(Two tailed test)
Test statistic = mean difference/std deviation
For 68% confidence level, }z}<1
Here z =3.40 >1
Hence reject null hypothesis
The difference between the means cannot be 0 and there is statistical evidence at 68% level to reject null hypothesis