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3 years ago

What is the surface area of the square pyramid below?

Mathematics

1 answer:

Reika [66]3 years ago

6 0

The surface area of square pyramid is the sum of the area of all its sides.

If l is the slant height and base is s each then surface area of pyramid is given by:

Surface area = s2+2xsx l

From the given figure in the question:

S=6 cm ,l= 8cm.

Substituting these values in surface area formula we have:

Surface area = 62+2x6x8

Surface area = 36+96

Surface area =132cm2

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I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

5 0

3 years ago

If I equals PRT which equation is equivalent to T

snow_lady [41]

I = P · R · T
Divide both sides by P·R
I/(P·R) = T

Answer: $\frac{I}{PR} = T$

7 0

3 years ago

Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.

VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

4 0

3 years ago

Read 2 more answers

I need help with this question please. I will mark brainliest for the first correct answer !

aleksandrvk [35]

What’s the question

3 0

3 years ago

Find the GCF of 48 and 42

ivann1987 [24]

Answer:

The gcf of 42 and 48 can be obtained like this:

The factors of 42 are 42, 21, 14, 7, 6, 3, 2, 1.

The factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.

The common factors of 42 and 48 are 6, 3, 2, 1, intersecting the two sets above.

In the intersection factors of 42 ∩ factors of 48 the greatest element is 6.

Therefore, the greatest common factor of 42 and 48 is 6.

Taking the above into account you also know how to find all the common factors of 42 and 48, not just the greatest.

Hope I helped

3 0

3 years ago

Read 2 more answers