Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
We'll say that months = n.
Make a set of the DVD's sold:
In month 1, Aaron sold 20 DVDs. There is no data for month 0.
There is a constant increase of 30 DVDs every month. We can make an equation out of this to fit this data set:
a represents the DVDs made.
We need to subtract 10 in this equation, as the starting point is 20, and the increase of 30 is different from the increase from n = 0 to n = 1.
We are looking for the amount of DVDs Aaron sold on the 13th month. Plug 13 into the equation:
The predicted number of DVDs Aaron will sell on the 13th month is
380.
Answer:
Step-by-step explanation:
That will be 3a + 3b + 3c pounds of mortar.
as there will be 3a pounds of water and 3c pounds of cement.
Answer:
$20.4
Step-by-step explanation:
20% of 17= 3.4
Add it to the initial $17 and you get $20.4
The meat would end up costing $35 because you want to multiply