Answer:
True.
Step-by-step explanation:
For example let f(x) = 3x + 1 then f-1(x) is found as follows
Let f(x) = y = 3x + 1 then
3x = y - 1
x = (y-1) / 3
x = f-1(x) = (x - 1)/3.
So:
Replacing the x in y by (x - 1)/3 :-
x = f(-1)(y) = ( (3x + 1) - 1) / 3
= 3x / 3
= x.
So y = f(x).
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - 
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= - 
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Answer:
Step-by-step explanation:
The radius it .5 of the diameter so in this case the radius is 11. The formula for area is pi*r^2= pi*11^2=pi*121=380.13
X=147
Angle x and 33 are a linear pair meaning they equal 180 and 180-33=147
