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ZanzabumX [31]
3 years ago
12

In the diagram, WZ=StartRoot 26 EndRoot.

Mathematics
1 answer:
gogolik [260]3 years ago
8 0

Answer:

P = 8 + 2\sqrt{26}

Step-by-step explanation:

Given

W = (-2, 4)

X = (2, 4)

Y = (1, -1)

Z = (-3,-1)

Required

The perimeter

First, calculate the distance between each point using:

d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2

So, we have:

WX = \sqrt{(-2- 2)^2 + (4-4)^2 } =4

XY = \sqrt{(2- 1)^2 + (4--1)^2 } =\sqrt{26}

YZ = \sqrt{(1- -3)^2 + (-1--1)^2 } =4

ZW = \sqrt{(-3--2)^2 + (-1-4)^2 } =\sqrt{26}

So, the perimeter (P) is:

P = 4 + \sqrt{26} + 4 + \sqrt{26}

P = 8 + 2\sqrt{26}

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Mr. Alen has a tank of volume 450 cm3. Convert the volume into “m3
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0.00045 m^{3}

Step-by-step explanation:

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4 0
3 years ago
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Two pipes are connected to the same tank. When working​ together, they can fill the tank in 4 hrs. The larger​ pipe, working​ al
Lena [83]

Answer:

It will take the smaller pipe 12 hours working alone

Step-by-step explanation:

In this question, we are asked to calculate the time it will take for a smaller pipe when working alone to fill a tank if the rate at which a larger one fills the tank is given and the rate at which they both fill when working together is given.

First, let’s represent the the volume to fill with say x cubic feet

When working together, their rate would be x/4

Now, the larger pipe can fill the tank in 6 hours less time. Let’s say the time taken for the smaller y, for the bigger, it definitely would be y-6

Hence rate of bigger will be x/(y-6)

For the smaller, the rate will be x/y

Now when we add both rates together, we have x/4 total rate for both

Let’s do tihis;

x/y + x/(y-6) = x/4

X(1/y + 1/y-6) = x(1/4)

1/y + 1/(y-6) = 1/4

y-6+y/(y(y-6) = 1/4

2y-6/y(y-6) = 1/4

Cross multiply;

4(2y-6) = y(y-6)

8y-24 = y^2 -6y

y^2 -6y -8y+24 = 0

y^2 -14y +24 = 0

y^2 - 2y-12y+24 = 0

y(y-2)-12(y-2) = 0

(y-12)(y-2) = 0

y = 12 or 2

y cannot be 2 because since it take the bigger 6 hours less, 2-6 = -4 is not possible as hours cannot be negative

8 0
3 years ago
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