What is the correct answer

EZ Car Rental charges $40 per day and $0.25 per mile driven. Ace Car Rental charges

Tema [17]

Answer:

B. 75

Step-by-step explanation:

When both cars travel 75 miles they both add up to $58.75

3 0

3 years ago

Two hiking groups made the purchases shown below. What is the cost of each item. GROUP 1: 6 muffins, 12 granola bars, Total=$26.

stepladder [879]

Answer:

Price of each muffin = $1.25

Price of each granola bar = $1.6

Step-by-step explanation:

Group 1:

6 muffins, 12 granola bars

Total money paid = $26.70

Group 2:

8 muffins, 15 granola bars,

Total money paid = $34.00

To find:

Price of each item?

Solution:

Let the price of one muffin = $ $x$

Let the price of one granola bar = $ $y$

As per group 1, the equation can be written as:

$6x+12y=26.70\\\Rightarrow x+2y=4.45 .... (1)$

As per group 2, the equation can be written as:

$8x+15y = 34$ .... (2)

Let us use elimination method to solve for $x$ and $y$ .

Multiplying equation (1) with 8 and subtracting (2) from it:

$16y-15y = 35.6 - 34\\\Rightarrow y = 1.6$

Using equation (1):

$x+3.2=4.45\\\Rightarrow x = 1.25$

Therefore, the answer is:

Price of each muffin = $1.6

Price of each granola bar = $1.25

7 0

3 years ago

I NEED TO HAND IN NOW!!!

umka21 [38]

Step-by-step explanation:

a)

total no. of pupils is not more than 24

therefore first equation is

(x+y) ≤ 24. ....(1)

No. of girls exceeding the no. of boys by atleast 4

(y-x) ≥ 4. .....(2)

b) Now Liza chooses 8 boys

Maximum no. of girls = ?

Using first inequality

y+8= 24 ( maximum value of less than or equal to function is equal to itself)

Therefore,

y= 24-8

=16

Minimum no. of girls = ?

Using second inequality

y-8 =4 (minimum value of greater than or equal to function is equal to itself)

Therefore,

y= 4+8

y=12

Answer:

a) 2linear inequalities

(x+y) ≤ 24

(y-x) ≥ 4

b) Max no. of girls = 16

Min no. of girls = 12

Hope it helps...

5 0

3 years ago

Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg

zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = average rent paid by 314 BYU students = $346

s = sample standard deviation = $86

n = sample of students = 314

$\mu$ = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, $\mu$ is ;

P(-2.082 < $t_3_1_3$ < 2.082) = 0.96

P(-2.082 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.082) = 0.96

P( $-2.082 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

P( $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

96% confidence interval for $\mu$ = [ $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $346 -2.082 \times {\frac{86}{\sqrt{314} } }$ , $346 +2.082 \times {\frac{86}{\sqrt{314} } }$ ]

= [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

5 0

3 years ago

What is the difference? StartFraction x 5 Over x 2 EndFraction minus StartFraction x 1 Over x squared 2 x EndFraction StartFract

Troyanec [42]

The difference of the given fraction is expressed as $\frac{x^2+4x-1}{x(x+2)}$

Given the expression:

$\frac{x+5}{x+2}-\frac{x+1}{x^2+2x} \\$

Take the LCM of the fraction to have:

$=\frac{x+5}{x+2}-\frac{x+1}{x(x+2)} \\=\frac{x(x+5)-(x+1)}{x(x+2)} \\=\frac{x^2+5x-x-1}{x(x+2)}\\=\frac{x^2+4x-1}{x(x+2)}$

Hence the difference of the given fraction is expressed as $\frac{x^2+4x-1}{x(x+2)}$

Learn more on fractions here; brainly.com/question/78672

7 0

2 years ago

Read 2 more answers