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goldenfox [79]
2 years ago
14

I need to show work real answers plz

Mathematics
2 answers:
Paul [167]2 years ago
6 0
X= -2 and y = -6. Here is the work
wolverine [178]2 years ago
3 0

Answer:

3x+2y-6x-2y=-18+24

-3x = 6

x=(-2)

x=(-2),1,

(3×-2)+2y=-18

2y=-18+6

2y=-12

y=(-6)

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The number of 3 million 3,000,000.

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X=-6 and x=1/3 are both correct values so A and D
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PLEASE HELP THIS IS TIMED<br> WHAT IS THE FOLLOWING SUM FIRST ONE IS QUESTION THE REST ARE CHOICES
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5 0
3 years ago
What is 246000000 in standed form need to know whit in 15 min
11Alexandr11 [23.1K]

Answer:

2.46×10^8

Step-by-step explanation:

The decimal point is here

246000000.

Then it must be moved up to here

2.46000000

Those are eight steps from where it was, so to compensate and make sure the number remains the same remove the zeros and multiply by 10^8

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2.46×10^8

3 0
3 years ago
List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct
zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

\sqrt{\dfrac{\left (n-1  \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1  \right )s^{2}}{\chi _{\alpha /2}^{}}}

s = \sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }

Where:

\bar x = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

\bar x = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = \sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} } = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }

\sqrt{\dfrac{\left (7-1  \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1  \right )2.854^{2}}{0.872}}

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

7 0
3 years ago
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