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Virty [35]
3 years ago
13

A radioactive nuclide is used to detect eye tumors. An atom of this radionuclide contains 15 protons, 15 electrons, and 17 neutr

ons. Which is symbol of this radionuclide?
Chemistry
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0
Knowing that the number of protons of an element is equivalent to its atomic number, it can be determined from the periodic table of elements that this radionuclide is phosphorus. Since the number of its neutrons is 17, it can also be determined that its atomic mass is n + p = 15 + 17 = 32. This means the isotope is phosphorus-32.
lapo4ka [179]3 years ago
6 0
The answer is phosphorus-32.

We know that the atom contains <span>15 protons, 15 electrons, and 17 neutrons.
To conclude of which element this radionuclide is, we need to know an atomic number of the element. The atomic number of the element is the number of proton in the nucleus of the atom. If the number of protons is 15, then the atomic number is 15. The element with atomic number 15 is phosphorus (according to the periodic table).
To conclude which phosphorus isotope this radionuclide is we need to know the mass number of the element. The mass number of the element is the sum of the number of protons and number of neutrons in the nucleus of the atom. If the number of protons is 15 and the number of neutrons is 17, then the mass number is 17 + 15 = 32.
Thus, this radionuclide is phosphorus-32.</span>
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Names of the sugar acid produced by the oxidation of d-ribose
jok3333 [9.3K]

Oxidation of D -Ribose in presence of hypobromous acid gives D-Ribonic acid

5 0
3 years ago
Given the balanced equation representing a reaction:
sleet_krkn [62]
4Al(s) + 3O2(g) --> 2Al2O3(s)    This is the balanced.
From the equation:

 4 moles of Al required 3 moles of O2 to produce 2 moles of Al2O3
 
3 moles of O2 reacted with 4 moles of Al to produce 2 moles of Al2O3
1 mole of O2 reacted with 4/3 moles of Al to produce 2/3 moles of Al2O3  (Divide by 3)
4.5 moles of O2 reacted with (4/3 *4.5) moles of Al to produce (2/3*4.5) moles of Al2O3

4.5 moles of O2 reacted with 6moles of Al to produce  3moles of Al2O3

(3) is the answer.  6 mol of Al.
7 0
3 years ago
Air at 25°C with a dew point of 10 °C enters a humidifier. The air leaving the unit has an absolute humidity of 0.07 kg of water
madreJ [45]

Explanation:

The given data is as follows.

         Temperature of dry bulb of air = 25^{o}C

          Dew point = 10^{o}C = (10 + 273) K = 283 K

At the dew point temperature, the first drop of water condenses out of air and then,

        Partial pressure of water vapor (P_{a}) = vapor pressure of water at a given temperature (P^{s}_{a})

Using Antoine's equation we get the following.

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{T(K) - 46.854}

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{283 - 46.854}

                               = 0.17079

                   P^{s}_{a} = 1.18624 kPa

As total pressure (P_{t}) = atmospheric pressure = 760 mm Hg

                                   = 101..325 kPa

The absolute humidity of inlet air = \frac{P^{s}_{a}}{P_{t} - P^{s}_{a}} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                  \frac{1.18624}{101.325 - 1.18624} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                 = 0.00735 kg H_{2}O/ kg dry air

Hence, air leaving the humidifier has a has an absolute humidity (%) of 0.07 kg H_{2}O/ kg dry air.

Therefore, amount of water evaporated for every 1 kg dry air entering the humidifier is as follows.

                 0.07 kg - 0.00735 kg

              = 0.06265 kg H_{2}O for every 1 kg dry air

Hence, calculate the amount of water evaporated for every 100 kg of dry air as follows.

                0.06265 kg \times 100

                  = 6.265 kg

Thus, we can conclude that kg of water the must be evaporated into the air for every 100 kg of dry air entering the unit is 6.265 kg.

3 0
3 years ago
Using the equation MgCl2 -&gt; Mg + Cl2, if 5.00 grams of MgCl2 is given, how many grams of Mg is produced?
motikmotik

Answer:

MgCl2-> Mg+Cl

mass 5.00g Mass=1.263g

RFM Mg=24+35.5 ×2= 95 RFM= 24

moles= 5.00÷ 95= 0.0526 Moles=0.0526

Explanation:

mas of Mg= 1.263 grams

4 0
3 years ago
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hammer [34]
1 doubling s will almost double the rate
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3 years ago
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