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Nataliya [291]
3 years ago
9

What is the energy of an electromagnetic wave with a frequency of 8•10^12 Hz?

Chemistry
1 answer:
aniked [119]3 years ago
8 0

Hello!

Find the Energy of the Photon by Planck's Equation, given:

E (photon energy) =? (in Joule)

h (Planck's constant) = 6.626*10^{-34}\:J * s

f (radiation frequency) = 8*10^{12}\:Hz

Therefore, we have:

E = h*f

E = 6.626*10^{-34}*8*10^{12}

E = 53.008*10^{-34+12}

E = 53.008*10^{-22}

\boxed{\boxed{E = 5.3008*10^{-21}\:Joule}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

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The half-cell reactions are:

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First we have to calculate the cell potential for this reaction.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}

where,

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R = gas constant = 8.314 J/mol.K

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n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = +0.63 V

E_{cell} = cell potential for the reaction = ?

[Zn^{2+}] = 3.5 M

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Now put all the given values in the above equation, we get:

E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

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