1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Whitepunk [10]
4 years ago
8

Which of the compounds above are strong enough acids to react almost completely with a hydroxide ion (pka of h2o = 15.74) or wit

h a bicarbonate ion (pka of h2co3 = 6.37)? enter your answers as an alphabetized string, i.e. abc, not cba; enter none if none of the compounds are strong enough acids?
Chemistry
1 answer:
Ksju [112]4 years ago
5 0
<h2>Answer:</h2>

Pyridinium will react with both OH- and HCO3-, whereas the ketones will only react with concentrated OH-, while Butan-2-one cannot react with either of above.

a) Butan-2-one: cannot react with both hydroxide ion and bicarbonate.

b) Pyridinium: can react with both hydroxide ion and bicarbonate.

c) ketones : can only react with concentrated OH-

You might be interested in
If the volume of an irregular sound is determined by the water displacement technique, its volume will be equal to
dolphi86 [110]
25 mL
i could be wrong but hope it helps
3 0
3 years ago
Complete the statement<br>qxy- bxy+cxy= xy( )​
andrey2020 [161]

Answer:

xy (-b+c+q) is the answer to this

3 0
4 years ago
Which element would have the largest radius; Br or Se? Explain
dusya [7]
The atomic radium increases to the left and downwards on the periodic table. 
By that logic, Se has the largest radius.
5 0
3 years ago
Which sample has particles with the lowest average kinetic energy?
Anastasy [175]
The question asks average kinetic energy. So it is only related with the temperature. The higher temperature is, the higher kinetic energy is. So the answer is (4).
3 0
3 years ago
Read 2 more answers
The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Otrada [13]

Answer:

25.2 kJ

Explanation:

The complete question is presented in the attached image to this answer.

Note that, the heat gained by the 2.00 L of water to raise its temperature from the initial value to its final value comes entirely from the combustion of the benzoic acid since there are no heat losses to the containing vessel or to the environment.

So, to obtained the heat released from the combustion of benzoic acid, we just calculate the heat required to raise the temperature of the water.

Q = mCΔT

To calculate the mass of water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat capacity of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

From the graph,

Final temperature of water = 25°C

Initial temperature of water = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0
3 years ago
Other questions:
  • Consider the word equation. calcium hydroxide + hydrochloric acid mc012-1.jpg calcium chloride + water Which is the correspondin
    5·2 answers
  • I need help if anyone would like to provide info
    6·2 answers
  • The data listed below are for mechanical waves. Which wave has the greatest energy? amplitude = 7 cm; wavelength = 12 cm; period
    14·2 answers
  • How many atoms are in 9.35 moles of lithium?
    7·1 answer
  • The world produces about 3.9 billion tons of food every year. Of that amount, approximately 2.6 billion tons is consumed each ye
    11·2 answers
  • The emission spectrum for an element is? Select all that apply
    8·1 answer
  • When baking soda and vinegar react, the product includes bubbles. what mostly likely occurred?
    9·1 answer
  • Which statement best describes displacement? Check all that apply
    14·1 answer
  • DHDHDHSHSHSHSVSVSBSHSHHAVAVABAVABAGAGAGAGAGAGABABABABBA
    8·2 answers
  • Helppp nowwww plsss!!!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!