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Ratling [72]
1 year ago
5

(2x² + 4x³) + (-4x² + 6x³ - 2)

Mathematics
1 answer:
klemol [59]1 year ago
6 0
Answer is:

10x - 2x - 2
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A 2-pound box of spaghetti costs $2.50. Philip says that the unit cost is 2 over 250 = $0.80 per pound. Explain his error
7nadin3 [17]
Phillip forgot to put a period between 2 and 50
4 0
3 years ago
Is 6 less than 6.00?
Nadya [2.5K]
No, they are the same value.
3 0
3 years ago
A(x, 1), B(5,3) and C(4,-3) are the vertices of triangle ABC. If AB=AC, find the value of x​
Molodets [167]

\\ \rm\longmapsto AB=AC

\\ \rm\longmapsto \sqrt{(x-5)^2+(1-5)^2}=\sqrt{(x-4)^2+(1+3)^2}

\\ \rm\longmapsto (x-5)^2+(-2)^2=(x-4)^2+4^2

\\ \rm\longmapsto (x-5)^2+4=(x-4)^2+16

\\ \rm\longmapsto (x-5)^2-(x-4)^2=16-4=12

\\ \rm\longmapsto x^2-10x+25-x^2+8x-16=12

\\ \rm\longmapsto -2x+9=12

\\ \rm\longmapsto -2x=12-9=3

\\ \rm\longmapsto x=\dfrac{3}{-2}=-1.5

5 0
3 years ago
Read 2 more answers
.What is the value of the expression below when x=9? Enter the answer as NUMBER only?<br> 1/3 x^2+4
belka [17]

Step-by-step explanation:

<u>1</u><u> </u>*9^2 + 4

3

<u>1</u><u> </u>* 81 + 4

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<u>1</u><u> </u>* 85

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<u>85</u>

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=28

5 0
3 years ago
Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box
pantera1 [17]
To find the z-score for a weight of 196 oz., use

z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2.  Carl is wondering about the percentage of boxes with weights ABOVE z = 2.  The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0
3 years ago
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