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3 years ago

Que piensas cuando escucha la palabra proteción

Chemistry

1 answer:

TEA [102]3 years ago

5 0

Answer:

pues yo pienso en protejerte de cualquier cosa y tener cuidado para que no te pase una tragedia ...

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Soonnnn pleaseeee 5 POINTSS EXTRAAAA!!! Please answer all 3 questionsss

aev [14]

Answer:

#4 is letter C

#5 is letter B

#6 is letter A

4 0

3 years ago

Photosynthesis needs water and carbon dioxide to happen. These 2 ingredients are called _______.

makvit [3.9K]

The answer is C. Reactants

6 0

3 years ago

What mass of carbon monoxide is needed to react with 2.08 kg of iron oxide? ----> Fe^2O^3 + 3CO --> 2Fe + 3CO^2

spayn [35]

Answer: The mass of carbon monoxide required is 1.094 kg

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of iron (III) oxide = 2.08 kg = 2080 g (Conversion factor: 1 kg = 1000 g)

Molar mass of iron (III) oxide = 159.69 g/mol

Plugging values in equation 1:

$\text{Moles of iron (III) oxide}=\frac{2080g}{159.69g/mol}=13.02 mol$

The given chemical equation follows:

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

By the stoichiometry of the reaction:

If 1 mole of iron (III) oxide reacts with 3 moles of CO

So, 13.02 moles of iron (III) oxide will react with = $\frac{3}{1}\times 13.02=39.06mol$ of CO

Molar mass of CO = 28.01 g/mol

Plugging values in equation 1:

$\text{Mass of carbon monoxide}=(39.06mol\times 28.01g/mol)=1094.07g=1.094kg$

Hence, the mass of carbon monoxide required is 1.094 kg

5 0

3 years ago

What volume of 3.25m naoh would be required to form 1 mole of na3po4

LUCKY_DIMON [66]

Answer: 0.923 L

Explanation: The reaction between naoh and h3po4 is:

3naoh + h3po4 —> na3po4 + 3h20

this means it requires 3 mols of naoh to make na3po4

given the concentration, 3.25 M, the equation looks like this:

3.0 mol x (1.0L/ 3.25mol) = 0.923 L

6 0

3 years ago

In the laboratory you dissolve 23.8 g of manganese(II) nitrate in a volumetric flask and add water to a total volume of 125 . mL

AleksandrR [38]

Answer:

The correct answer is 1.06 M

Step-by-step explanation:

We have to calculate the molarity (M), which is:

M= moles solute/ 1 L solution.

The chemical formulae of manganese (II) nitrate is Mn(NO₃)₂. So, we first calculate its molecular weight (Mw) as follows:

Mw(Mn(NO₃)₂)= molar mass Mn + (2 x molar mass N) + (6 x molar mass N)= 55 g/mol + (2 x 14 g/mol) + (6 x 16 g/mol) = 179 g/mol

Then, with Mw we calculate the number of moles there is in the given mass of Mn(NO₃)₂:

moles Mn(NO₃)₂= mass/Mw= 23.8 g/(179 g/mol)= 0.133 mol

Now, we need the final volume in liters, so we convert the volume from mL to L:

125 mL x 1 L/1000 mL = 0.125 L

Finally, we divide the moles of Mn(NO₃)₂ into the volume in L, to obtain the molarity in mol/L:

M= 0.133 moles/0.125 L = 1.06 mol/L= 1.06 M

7 0

3 years ago

Que piensas cuando escucha la palabra proteción​

Que piensas cuando escucha la palabra proteción