Answer:
Pyrophoricity is a property of metals and oxides of lower oxidation states, including radioactive ones, in which they spontaneously ignite during or after stabilization.
Emission spectrum results from the movement of an electron from a higher to a lower energy level. The frequency of the photon is 5.5 * 10^14 Hz.
From the formula;
E = hc/λ
h = Plank's constant =
Js
c = speed of light= 
λ = wavelength =
m
E = 
E =
J
Also;
E =hf
Where;
h = Planks's constant
f = frequency of photon
f = E/h
f = 
f =
Hz
Learn more: brainly.com/question/18415575
Answer:
d
. Sc2O5
Explanation:
Hello,
In this case, when forming oxides from a metal and oxygen, for us to find out each element's subscript, we must exchange them as shown below, considering +5 for scandium:

For that reason, the answer is d
. Sc2O5
Best regards.