Explanation:
The given reaction is as follows.

Initial : 0.160 0.160 0
Change : -x -x 2x
Equilibrium: 0.160 - x 0.160 - x x
It is given that
= [0.160 - x] = 0.036 M
and,
= [0.160 - x] = 0.036 M
so, x = (0.160 - 0.036) M
= 0.124 M
As, [HI] = 2x.
So, [HI] = 
= 0.248 M
As it is known that expression for equilibrium constant is as follows.
![K_{eq} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BHI%5D%5E%7B2%7D%7D%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D)
= 
= 47.46
Thus, we can conclude that the equilibrium constant, Kc, for the given reaction is 47.46.
Explanation:
A compound that contains more stronger bonds will need more amount of heat in order to break the bonds so that it changes into vapor state.
In 1-propanol, there is hydrogen bonding and it is stronger in nature. As a result, more amount of heat is required to break the bonds between molecules of 1-propanol.
Whereas in propanone, there will be dipole-dipole interactions which are less stronger than hydrogen bonding. Hence, propanone molecule will need less amount of energy than 1-propanol.
On the other hand, pentane will need more amount of heat as it has longer chain of carbon atoms as compared to methane.
Thus, we can conclude that given compounds are arranged in order of increasing vapor pressure as follows.
methane < pentane < propanone < 1-propanol
Mass = PROTONS + neutrons. So, 19 +20 = 39.
(Don't confuse yourself between electrons and protons when they are equal because it could be an ion)
Unit cells.
They are the smallest group of atoms that take form of a crystal and can repeat in 3 dimensions.
Answer:
28.9 g
Explanation:
We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.
<em>Gather all the information in one place</em> with molar masses above the formulas and masses below them.
: 159.69 28.01
Fe₂O₃ + 3CO ⟶ 2Fe + 3CO₂
Mass/g: 55.0
1. Use the molar mass of Fe₂O₃ to calculate the moles of Fe₂O₃.

2. Use the molar ratio of CO:Fe₂O₃ to calculate the moles of CO.

3.Use the molar mass of CO to calculate the mass of CO.