(-9)+(-6)+(-4)+(-1) is the expression and (-20) is the sum
A = P*(1 +r/n)^(n*t)
A = $8,600*(1 +.031/4)^(4*15)
A ≈ $13,700
About $13,700 will be in Jocelyn's account after 15 years.
Answer:
angles KKL & FGE
Step-by-step explanation:
Alternate Exterior Angles (AEA) are a pair of angleson the outer side of each of those two lines but on opposite sides of the transversal.
Thus for this question the AEA are:
angles KJL & FGE
Answer:
the correct answer is 120 square meters
Step-by-step explanation:
DG is a half diagonal and it intersects with the other diagonal at 90°. So it forms a right angle triangle. Using Pythagoras theorem
13^2-5^2=d^2
169-25=d^2
144=d^2
d=√144
d=12
so the other half diagonal is 12m
the two diagonals will be 2×5 and 2×12
the two diagonals will be 10m and 24m
area of a rhombus=1/2d1d2
area of the rhombus= 1/2×10×24
area of the rhombus=120 square meters
Answer:
Purchases greater than 66.67 dollars should use coupon 2, while purchases between 20 dollars and 66.67 should use coupon 1.
Step-by-step explanation:
Coupon 1 must be used as long as those 10 dollars represent more money than 15% of coupon 2.
For example, if the purchase is the minimum of $ 20, 10 dollars represents half of the purchase, therefore in this case it is better to use coupon 1.
In this case, coupon 2 would only be a discount of 3 dollars (20 * 0.15).
So when from what value would it be better to use coupon 2, it would have to be calculated when it is worth more than 10 dollars.
10 = x * 0.15
x = 10 / 0.15
x = 66.67
That is to say that from the purchases greater than 66.67 dollars, coupon 2 would have a discount equivalent to 10 dollars or more.
