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1. The value of (301)^2 – (300)^2 is

Ganezh [65]

Answer:
(301)^2-(300)^2
it is in the form of
a^2-b^2=(a+b)(a-b)
so,
(301+300)(301-300)
(601)(1)=601

7 0

3 years ago

A tortoise takes 1 1/4 hours to walk 5/6 miles. At this rate, how long does it take her to walk 1 mile?

Illusion [34]

Answer:

I think it is 3/2

Step-by-step explanation:

1 1/4 ÷ 5/6

5/4 × 6/5 = 30/20= 3/2

3 0

2 years ago

how can I find the smallest division of a measurement without a ruler? for eg. 12.45cm, what's the smallest division?

vladimir1956 [14]

Answer:

Step-by-step explanation:

mm

5 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

You are parasailing for the first time. The rope that connects you to the boat is 38 feet long. The distance along the water bet

Xelga [282]

Answer:

About 30.98386677 ft above the water.

Step-by-step explanation:

Use pythagorean theorem, a^2+b^2=c^2.

So when you plug in the numbers it would be x^2+22^2=38^2. Move 22^2 to the right side giving you x^2=38^2-22^2. Then subtract and take the square root of x^2.

5 0

2 years ago