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Alina [70]
3 years ago
14

Kristl has saved 30%

Mathematics
1 answer:
Tom [10]3 years ago
4 0

Answer:

$180

Step-by-step explanation:

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Solve the inequality -2x<16
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X > -8

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divide both side by -2
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Step-by-step explanation:

I hope it's helpful for you

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Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1
ivolga24 [154]

Answer:

a^{3y} + 1  = (a^{y}+1 )^{3}  - 3a^y(a^{y}+1)\\\\

Step-by-step explanation:

We are to factorize the expression a^{3y} + 1 completely. To do this, we will apply the expression below;

The expression can be rewritten as a^{3y} + 1^{3}

To factorize the expression, we need to first factorize (a^{y}+1 )^{3} first

(a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2}  } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3}  = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3}  = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\

The we will make a^{3y} + 1^{3} the subject of the formula as shown;

(a^y)^{3} + 1 = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3}  = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\\\

(a^y)^{3} + 1  = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\\\

a^{3y} + 1  = (a^{y}+1 )^{3}  - (3(a^y)^{2}+3a^y)\\\\

a^{3y} + 1  = (a^{y}+1 )^{3}  - 3a^y(a^{y}+1)\\\\

This last result gives the expansion of the expression

7 0
3 years ago
What is the image on segment Oj rotated 270 counterclockwise around point 0?
inysia [295]

Answer:

OL and M

Step-by-step explanation:

(1)

270° ÷ 30° = 9

Count 9 dashed lines from OJ counterclockwise, then

OJ → OL

(2)

120° ÷ 30° = 4

Count 4 dashed lines from R counterclockwise, then

R → M

6 0
3 years ago
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