This is an arithmetic sequence with a common difference of 1.23...that means u add 1.23 to each term to find the next term.
1.31 + 1.23 = 2.54
2.54 + 1.23 = 3.77
3.77 + 1.23 = 5 <== ur next term
Problem 1
<h3>Answer: 7.3</h3>
Explanation: Apply the square root to the area to get the side length. This only applies to areas that are squares (hence the name).
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Problem 2
<h3>Answer: C) 1.3</h3>
Explanation: Use your calculator to find that choices A,B,D plugged into the square root function yield terminating decimal values. "Terminating" means "stop". This implies that they are perfect squares (though not perfect squares in the sense of whole number perfect squares which you may be used to). Choice C is the only value that has a square root that leads to a non-terminating decimal. The digits of this decimal go on forever without any pattern. The value is irrational.
- sqrt(5.29) = 2.3 terminating decimal
- sqrt(13.69) = 3.7 terminating decimal
- sqrt(1.3) = 1.140175425 keeps going forever without any pattern
- sqrt(0.09) = 0.3 terminating decimal
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Problem 3
<h3>Answer: 23.6 feet approximately</h3>
Explanation: Apply the square root to 15.5 to get roughly 3.937; this is the approximate side length of one square. Six of these tiles placed together will lead to a total length of roughly 6*3.937 = 23.622 which rounds to 23.6 feet. Like with problem 1, the square root being used like this only works for square areas.
Answer:
yards because it can't be squared if its a circle
Step-by-step explanation:
Answer:
34/112 or 17/56
Step-by-step explanation:
( total 12 graders + total swim team ) - (12 grade and swim team)
26/112 + 16/112 - 8/112
42/112 - 8/112
34/112
Answer:
There are 880 workers at the company.
Step-by-step explanation:
With the information provided, you can find the total amount of workers at the company which would represent 100% using a rule of three given that 88 workers represent 10% of workers:
88 workers → 10%
x ← 100%
x=(88*100)/10= 880
According to this, the answer is that there are 880 workers at the company.
